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Virty [35]
3 years ago
7

Log(3+√5) + log(3 - √5) = ?​

Mathematics
1 answer:
VashaNatasha [74]3 years ago
8 0

Given that

log (3+√5) + log (3-√5)

We know that

log ab = log a + log b

⇛log [(3+√5)(3-√5)]

This is in the form of (a+b)(a-b)

Where a = 3 and b = √5

We know that

(a+b)(a-b) = a²-b²

⇛log [(3)²-(√5)²]

⇛log(9-5)

⇛log 4

<u>Answer</u> :- log (3+√5) + log (3-√5) = log 4

<u>also</u><u> read</u><u> similar</u><u> questions</u><u>:</u> log(5) + log(3) rewrite the following in the form log(c)....

brainly.com/question/857062?referrer

witch of the following expression is equivalent to the logarithmic expression below. log(3)5/x^2 A)log(3) 5+2 log(3)x B)log(3) 5-2 log(3)x C)2 log(3) 5 -log(3)x...

brainly.com/question/10025117?referrer

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Explain why the "+ C" is not needed in the antiderivative when evaluating a definite integral.
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The reason the "+ C" is not needed in the antiderivative when evaluating a definite integral is; The C's cancel each other out as desired.

<h3>How to represent Integrals?</h3>

Let us say we want to estimate the definite integral;

I = \int\limits^a_b {f'(x)} \, dx

Now, for any C, f(x) + C is an antiderivative of f′(x).

From fundamental theorem of Calculus, we can say that;

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Help please! any1 know this​
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The only option that fits is E, because:

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