Log(3+√5) + log(3 - √5) = ?
1 answer:
Given that
log (3+√5) + log (3-√5)
We know that
log ab = log a + log b
⇛log [(3+√5)(3-√5)]
This is in the form of (a+b)(a-b)
Where a = 3 and b = √5
We know that
(a+b)(a-b) = a²-b²
⇛log [(3)²-(√5)²]
⇛log(9-5)
⇛log 4
<u>Answer</u> :- log (3+√5) + log (3-√5) = log 4
<u>also</u> <u> read</u> <u> similar</u> <u> questions</u> <u>:</u> log(5) + log(3) rewrite the following in the form log(c)....
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witch of the following expression is equivalent to the logarithmic expression below. log(3)5/x^2 A)log(3) 5+2 log(3)x B)log(3) 5-2 log(3)x C)2 log(3) 5 -log(3)x...
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