Question

How would you simplify this:

Answer 1

Hello!

You need to rationalize this.

to rationalize you multiply a conjugant or a another term to get a radical under the denominator.

Here is the process shown below:

$\frac{\sqrt{4} }{\sqrt[3]{4} } *\frac{\sqrt[3]{4^{2}} }{\sqrt[3]{4^{2} }} = \frac{\sqrt{4}* \sqrt[3]{4^{2} } }{4} = \frac{2\sqrt[3]{16} }{4} =\frac{2\sqrt[3]{8*2} }{4} =\frac{2*2\sqrt[3]{2} }{4} =\frac{4\sqrt[3]{2} }{4} = \sqrt[3]{2}$

The answer is $\sqrt[3]{2}$

I hope this helps!

Have a great day!