An Olympic high jumper leaps over a horizontal bar. The jumper's center of mass is raised 0.25 m during the jump. Calculate the
1 answer:
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Answer:
a . 0.35cm
b. 11.33cm
Explanation:
a. Given both currents are in the same direction, the null point lies in between them. Let x be distance of N from first wire, then distance from 2nd wire is 4-x
#For the magnetic fields to be zero,the fields of both wires should be equal and opposite.They are only opposite in between the wires:
Hence, for currents in same direction, the point is 0.35cm
b. Given both currents flow in opposite directions, the null point lies on the other side.
#For the magnetic fields to be zero,the fields of both wires should be equal and opposite.They are only opposite in outside the wires:
Let x be distance of N from first wire, then distance from 2nd wire is 4+x:
Hence, if currents are in opposite directions the point on x-axis is 11.33cm
Answer:
The maximum change in flux is
The average induced emf
Explanation:
From the question we are told that
The speed of the technician is
The distance from the scanner is
The initial magnetic field is
The final magnetic field is
The diameter of the loop is
The area of the loop is mathematically represented as
At maximum the change in magnetic field is mathematically represented as
=>
The average induced emf is mathematically represented as