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bija089 [108]
3 years ago
13

a mass on a spring vibrates in simple harmonic motion at an amplitude of 8.0 cm. if the mass of the object is 0.20kg and the spr

ing constant is 130N/m, what is the frequency?
Physics
1 answer:
Reil [10]3 years ago
5 0

Answer:

4.06 Hz

Explanation:

For simple harmonic motion, frequency is given by

f=\frac {1}{2\pi}\times \sqrt{\frac {k}{m}} where k is spring constant and m is the mass of the object.

Substituting 0.2 Kg for mass and 130 N/m for k then

f=\frac {1}{2\pi}\times \sqrt{\frac {130}{0.2}}=4.057670803\\f\approx 4.06 Hz

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The answer would be: element helium
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3 years ago
Along the remote Racetrack Playa in Death valley, California,stones sometimes gouge out prominent trails in the desert floor, as
MArishka [77]

Answer:

Explanation:

given ;

  • coefficient of kinetic friction = 0.80
  • mass m = 26kg
  • considering the force acting in horizontal direction and from newton's 2nd law of motion;
  • for vertical motion = Fn - mg = 0
  • for horizontal motion = F = ma + miu mg = m( a + miu.g)
  • but a = 0
  • therefore, F = miu mg where g = 9.81m/s^2
  • plugging the values into the equation;
  • F = 0.80 x 9.81 x 26

Horizontal force = 204.05N

3 0
3 years ago
A bar B made of some material is attracted by a magnet. Is the bar B magnetised ?​
Dvinal [7]

Answer:

No, it is not magnetized.

Explanation:

Bar B does not necessarily have to be magnetized before it can be attracted to a magnet. It just has to be a magnetic material such as Iron.

If bar B were magnetized, it could either be attracted or repelled by the magnet since this would depend on the side of the pole of bar B facing it.

Since we are not given any information about bar B other than it is attracted to the magnet, it is thus not magnetized.

7 0
3 years ago
Two forces, 80N and 100N acting at an angle of 60 degrees with each other, pull on an object. What single force would replace th
KIM [24]

We use the law of Cosines, resultant force

F =\sqrt{(F_{1})^2 + (F_{2})^2 + 2 F_{1} F_{2} cos  \theta   }

Here, (F_{1}) and (F_{2}) are forces acting at angle \theta with each other.

Given F_{1} = 80 N, F_{2} = 100 N and \theta = 60^0.

Substituting these given values in above formula we get

F =\sqrt{(80)^2 + (100)^2 + 2 \times 80 \times 100 \ cos 60^0     } = 156. 20 \ N.

Thus, the resultant force is 156 N.

8 0
4 years ago
A force of 70 N is inclined at an angle
Bad White [126]

Answer:

The horizontal component of the 70 N force = 35·√3 N

The vertical component of the 70 N force = 35 N

Explanation:

The magnitude of the given force, F = 70 N

The angle of inclination of the given force to the horizontal, θ = 30°

By the resolution of forces, we can resolve the given force, F, into its horizontal component, Fₓ, and vertical components, F_y, as follows;

The horizontal component of the given force = Fₓ = F × cos(θ)

Substituting the values, we have;

The horizontal component of the 70 N force, Fₓ = 70 × cos(30°) = 35·√3 N

The vertical component of the given force = F_y = F × sin(θ)

Substituting the values, we have;

The vertical component of the 70 N force, F_y = 70 × sin(30°) = 35 N.

5 0
3 years ago
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