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bija089 [108]
3 years ago
13

a mass on a spring vibrates in simple harmonic motion at an amplitude of 8.0 cm. if the mass of the object is 0.20kg and the spr

ing constant is 130N/m, what is the frequency?
Physics
1 answer:
Reil [10]3 years ago
5 0

Answer:

4.06 Hz

Explanation:

For simple harmonic motion, frequency is given by

f=\frac {1}{2\pi}\times \sqrt{\frac {k}{m}} where k is spring constant and m is the mass of the object.

Substituting 0.2 Kg for mass and 130 N/m for k then

f=\frac {1}{2\pi}\times \sqrt{\frac {130}{0.2}}=4.057670803\\f\approx 4.06 Hz

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We want to explain why two different observes may measure different frequencies for the same vibrating object.

We will see that the two correct options are:

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<em />

Let's assume that the vibrating object is a guitar string. Thus, the string makes a noise, and from that noise, we can estimate the frequency at which the string vibrates.

Now there appears a really cool effect, called the Doppler Effect. It says that the apparent change of frequency is <u>due to the motion of the observer or the source of the frequency (or both).</u>

For example, if you move towards the vibrating string, the perceived frequency will be larger, and you will hear a "higher" sound.

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So, why do observers A and B measure different frequencies?

The two correct answers are:

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Given that earth's mass was half its actual value but its radius stayed the same. The escape velocity will be calculated as below:-

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