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bezimeni [28]
3 years ago
15

X-14=42 x=56 56______a solution

Physics
1 answer:
vodomira [7]3 years ago
7 0
A + b = 56, 3a = b, therefore 4a = 56, 56/4 = 14, 14 * 3 = 42, a = 14, b = 42.
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A cannon is fired from a castle wall at some unknown height above the ground. The cannonball leaves the cannon with speed 30.0m/
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Answer:

Part a)

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Part b)

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Part C)

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Part d)

In horizontal direction velocity will remain constant

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in vertical direction we have

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Explanation:

Part a)

Horizontal speed of the cannon

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\theta = 30^o

now we have

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vertical speed = v_y = vsin30 = 30 sin30 = 15 m/s

now the time taken by it to cover the distance 100 m from the wall

x = v_x t

100 = 25.98 t

t = 3.85 s

Part b)

Since it hits the ground in the same time

so the height of the castle is given as

h = \frac{1}{2}gt^2

h = \frac{1}{2}(9.81)(3.85^2)

h = 72.67 m

Part C)

At highest point of the projection

the vertical component of the velocity will become zero

so we will have

v_x = 25.98 m/s

v_y = 0

Part d)

In horizontal direction velocity will remain constant

so we have

v_x = 30 cos30 = 25.98 m/s

in vertical direction we have

v_y = v_i + at

v_y = 15 - 9.81(3.85)

v_y = -22.77 m/s

Part e)

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