Answer: The velocity at different marked time points are given as
t1 = -
t2 = +
t3 = +
t4 = -
t5 = 0
Explanation:
The slope of the tangent of the curve indicates the instantaneous velocity. So if the slope of the tangent is positive, that Is, the tangent makes a positive angle (above the horizontal axis) with the horizontal
axis, then the velocity at this point is positive, and if the slope of the tangent is negative, that is the tangent makes a negative angle with the horizontal axis (below the horizontal axis), then the velocity at this point is negative.
When the tangent of the line is parallel to the horizontal axis, the velocity is 0.
From the position-time graph attached, the sign on the instantaneous velocity for each time marked on the graph is given below
t1 = -
t2 = +
t3 = +
t4 = -
t5 = 0
QED!
Answer:
The answer is 11N to the right
Explanation:
Because 4N-3N= 1N
Therefore, 12N-1N=11N
The netforce is 11N to the right, because the greatest force is 12N to the right so it is more likely that the object is being pulled to the right.
Answer:
The concentration of OH⁻ in the mixture is 0.05 M
Explanation:
The reaction of neutralization between HCl and NaOH is the following:
H⁺(aq) + OH⁻(aq) ⇄ H₂O(l)
The number of moles of HCl is:

Similarly, the number of moles of NaOH is:

Now, from the reaction of HCl and NaOH we have the following number of moles of NaOH remaining:

Finally, the concentration of OH⁻ in the mixture is:
Therefore, the concentration of OH⁻ in the mixture is 0.05 M.
I hope it helps you!