All categories

3 years ago

Which statement can be supported by using a position-time graph?

Physics

1 answer:

MArishka [77]3 years ago

4 0

Answer:

Explanation:

Think about the equation for velocity. Its the change in position over the change in time. And now think about the formula for slope, its the change in y over the change in x. Now, if you have a position vs time graph, the slope is position over time, the direct formula for velocity. Therefore, the slope of a position vs time graph gives the velocity in that interval. You could take the derivative at that point and get the instantaneous velocity.

In the first argument, the only way to get a negative slope is if youre moving to the left of your initial position as you pass through time. So the claim isnt necessarily true. When you move away from the origin, that simply means youre moving through time.

In the second argument, a horizontal slope means the value is 0. That means there is a value of 0 for your velocity, aka standing still.

In the third argument, a positive slope means youre moving to the right of your initial position as you go through time.

The fourth one is incorrect. Speed is the magnitude of velocity, and the slope can be determined an any point besides vertical slopes, which would require time to literally stop.

I dont understand the very last part of what you posted, so try to make a decision based on what I just explained to you

You might be interested in

Help

Mama L [17]

<h3><u>Answer;</u></h3>

producing a path for current to flow

<h3><u>Explanation;</u></h3>

An AC generator is a device that converts mechanical energy into electrical energy using the principle of electromagnetic induction.
<em><u>Slip rings are two hollow rings to which two ends of the armature coil are connected. These rings rotate with the rotation of the coil. They function to to allow for electrical contact with the brushes.</u></em>
Slip rings therefore, provide a means for connecting the rotating armature to an external circuit.

3 0

4 years ago

Read 2 more answers

An 20-cm-long Bicycle Crank Arm. With A Pedal At One End. Is Attached To A 25-cm-diameter Sprocket, The Toothed Disk Around Whic

malfutka [58]

To solve the problem, it is necessary to apply the concepts related to the kinematic equations of the description of angular movement.

The angular velocity can be described as

$\omega_f = \omega_0 + \alpha t$

Where,

$\omega_f =$ Final Angular Velocity

$\omega_0 =$ Initial Angular velocity

$\alpha =$ Angular acceleration

t = time

The relation between the tangential acceleration is given as,

$a = \alpha r$

where,

r = radius.

PART A ) Using our values and replacing at the previous equation we have that

$\omega_f = (94rpm)(\frac{2\pi rad}{60s})= 9.8436rad/s$

$\omega_0 = 63rpm(\frac{2\pi rad}{60s})= 6.5973rad/s$

$t = 11s$

Replacing the previous equation with our values we have,

$\omega_f = \omega_0 + \alpha t$

$9.8436 = 6.5973 + \alpha (11)$

$\alpha = \frac{9.8436- 6.5973}{11}$

$\alpha = 0.295rad/s^2$

The tangential velocity then would be,

$a = \alpha r$

$a = (0.295)(0.2)$

$a = 0.059m/s^2$

Part B) To find the displacement as a function of angular velocity and angular acceleration regardless of time, we would use the equation

$\omega_f^2=\omega_0^2+2\alpha\theta$

Replacing with our values and re-arrange to find $\theta,$

$\theta = \frac{\omega_f^2-\omega_0^2}{2\alpha}$

$\theta = \frac{9.8436^2-6.5973^2}{2*0.295}$

$\theta = 90.461rad$

That is equal in revolution to

$\theta = 90.461rad(\frac{1rev}{2\pi rad}) = 14.397rev$

The linear displacement of the system is,

$x = \theta*(2\pi*r)$

$x = 14.397*(2\pi*\frac{0.25}{2})$

$x = 11.3m$

5 0

4 years ago

What is the specific heat of water?

Sergeeva-Olga [200]

Answer:

A) 4.18 J/g°C

Explanation:

8 0

3 years ago

Read 2 more answers

When is the universal theme of a story often revealed?

elena-14-01-66 [18.8K]

It is often revealed <span>at the resolution of the story, when the reader can see how the story ends.</span>

7 0

3 years ago

Read 2 more answers

The electron structures of atoms are not involved in the emission of:

nekit [7.7K]

The correct one is gamma rays. Lets go over them one by one.

Gamma rays are rays that arise from gamma decay, a type of radioactive decay. Often, after another decay, the nucleus is still unstable and it gives off energy in the form of gamma rays to stabilize itself. Hence, gamma rays have nothing to do with the electron structure, only with the nucleus of the atom.

X-rays are the product of accelerating electrons, hence only specific atoms can emit a specific energy of X-rays; similarly for the photoelectric phenomenon, the energy which is needed for photoelectrons to be created depends on the electron structure of the atom (in both cases, it is important to see how strong the bond between electron and atom is).
Finally, spectral lines differ depending on the electron structure of the atoms since electrons with different energies absorb different frequencies of light.

7 0

3 years ago