1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
rosijanka [135]
3 years ago
6

Energy can interact with objects and cause them to ________ or change

Chemistry
1 answer:
scoundrel [369]3 years ago
6 0

Answer:contact forces or transfer energy(not sure)

Explanation:

You might be interested in
Chemical reactions constantly take place all around us—and even inside us. Many
Alika [10]

Answer:

I don't think you can go on without doing a reaction since you touch really anything so no you can not go without any chemical reaction I think this is the answer

5 0
3 years ago
Can salt dissolve in hydrogen peroxide? Pls help me
Genrish500 [490]

Answer:

Yes it can!!

Explanation:

Hydrogen peroxide mixed with sodium is known as oxygen bleach. Add water and the compound releases an oxygen molecule to help it lift mold and stains from the surface of natural materials.

3 0
3 years ago
Name the parts of an electromagnet
Oxana [17]

Answer:

The iron core, copper wire, and an electricity source.

Explanation: Me

7 0
3 years ago
What is the rate law for the reaction 2A + 2B + 2C --> products
-Dominant- [34]

Answer:

R = 47.19 [A]*([B]^2)*[C]

Explanation:

The rate law for the reaction 2A + 2B + 2C --> products

Is being sought.

The reaction rate R could be expressed as  

R = k ([A]^m)*([B]^n)*([C]^p)                      (1)

where m, n, and p are the reaction orders with respect to (w.r.t.) components A, B and C respectively. This could be reduced to

R = ka ([A]^m)                   (2)

Where ka=(k[B]^n)*([C]^p);    

R = kb ([B]^n)                    (3)

Where kb=(k[A]^m)*([C]^p); and  

R = kc ([C]^p)                     (4)

Where kc=(k[A]^m)*([B]^n).

Equations (2), (3) and (4) are obtained for cases when the concentrations of two components are kept constant, while only one component’s concentration is varied. We can determine the reaction wrt each component by employing these equations.  

The readability is very much enhanced when the given data is presented in the following manner:

Initial [A]  0.273   0.819   0.273   0.273

Initial [B]  0.763   0.763   1.526   0.763

Initial [C]  0.400   0.400    0.400   0.800

Rate           3.0       9.0       12.0       6.0

Run#  1  2 3  4

Additional row is added to indicate the run # for each experiment for easy reference.

First, we use the initial rate method to evaluate the reaction order w.r.t. each component [A], [B] and [C] based on the equations (2), (3) and (4) above.

Let us start with the order wrt [A]. From the given data, for experimental runs 1 and 2, the concentrations of reactants B and C were kept constant.

Increasing [A] from 0.273 to 0.819 lead to the change of R from 3.0 to 9.0, hence we can apply the relation based on equation (2) between the final rate R2, the initial rate R1 and the final concentration [A2] and the initial concentration [A1] as follows:

R2/R1=ka[A2]^m/ka[A1]^m=([A2]/[A1])^m

9.0/3.0 = (0.819/0.273)^m

3 = (3)^m = 3^1  -> m = 1

Similarly, applying experimental runs 1 and 3 could be applied for the determination of n, by employing equation (3):  

R3/R1=kb[B3]^n/kb[B1]^n=([B3]/[B1])^n

12/3= (1.526/0.763)^n

4= 2^n, -> n = 2

And finally for the determination of p we have using runs 4 and 1:

R4/R1=kc[C4]^p/kc[C1]^p=([C4]/[C1])^p

6/3= (0.8/0.4)^p

2= 2^p , -> p = 1

Therefore, plugging in the values of m, n and p into equation (1), the rate law for the reaction will be:

R = k [A]*([B]^2)*[C]

The value of the rate constant k could be estimated by making it the subject of the formula, and inserting the given values, say in run 1:

k = R /( [A]*([B]^2)*[C]) = 3/0.273*(0.763^2)*0.4 =

47.19

Finally, the rate law is

R = 47.19 [A]*([B]^2)*[C]

7 0
4 years ago
Emerald-green crystals of the substance are used in nickel plating. what is the chemical name of this compound
nlexa [21]

The answer is nickel sulfate hexahydrate.

The chemical name of the substance is nickel sulfate hexahydrate.

Emerald-green crystals of the substance are used in nickel plating. The chemical name of this compound nickel sulfate hexahydrate.

This substance is used in nickel panting and it is having chemical name that is nickel sulfate hexahydrate.

3 0
3 years ago
Other questions:
  • Need chem help asap, thanks
    11·1 answer
  • 2 KCIO3 - 2 KCl + 302;<br>Type of Reaction?<br><br>​
    8·1 answer
  • One useful tool that may help a scientist interpret data by revealing unexpected patterns is a
    10·1 answer
  • The 1995 Nobel Prize in Chemistry was shared by Paul Crutzen, F. Sherwood Rowland, and Mario Molina for their work concerning th
    15·1 answer
  • What are the three examples of alloy
    7·1 answer
  • If oil stay on top of water if we put oil on our foot would we float?
    7·1 answer
  • In lecture we discussed two aspects of the critical concentration. What is the relationship between the critical concentration a
    12·1 answer
  • The Law of states that if two elements can combine to form two different compounds, the masses of the one
    7·2 answers
  • What brown substance in a cigarette causes lung cancer?
    10·2 answers
  • 2SO2 + O2 &gt; 2SO3 + heat add more SO3 is it a reactant product or no change
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!