Correct Answer: Option C
Reason:
<span>The </span>Pauli Exclusion Principle<span> states as '<em>in an atom or molecule, no two electrons can have the same four electronic quantum numbers. Further, an orbital can contain a maximum of only two electrons, the two electrons must have opposing spins.</em>'
</span>
Thus, it can be seen that in option C, electrons in last 2 subshell have electrons with same spin, which is a violation of Pauli Exclusion Principle .
Answer:
1.35 moles
Explanation:
Calculate how many
of potassium (K) are present in a sample of 8.12x10^23 atoms of K
6.02 X 10^23 atoms are 1 mole. how many 6.02 X 10^23 are in
8.12 X 10^23
divide 8.12 X 10^23 into sets of 6.02 X 10^23
(8.12 X 10^23)/(6.02 X 10^23) =1.35 moles
<h2>
Answer:</h2>
Hydroxide ions.
<h2>
Explanation:</h2>
- When base reacts with water they form hydroxide ion.
- For example, NH₃ + H₂O ----------> NH₄⁺ + OH⁻
(Ammonia) (Water) (Ammonium) (Hydroxide ion).
- In case of strong and week base, generally weak bases partially reacts with water to produce hydroxide ions. Whereas strong base completely reacts with water to produce hydroxide ions And the reaction between a strong acid and a strong base produces salt and water and reaction is called neutralization reaction as both acid and base get neutralized.
Result: On reaction of base with water gives hydroxide ion.
The question is incomplete, the complete question is shown in the image attached.
Answer:
7.69%
Explanation:
The balanced equation of this reaction is shown in the image attached to this answer.
The reaction is redox because we can notice a change in the oxidation number of species from left to right in the reaction equation.
For instance, the oxidation number of oxygen was changed from -1 in H2O2 to zero in O2. Hence H2O2 was oxidized.
To calculate the percentage of H2O2 in the sample;
number of moles of KMnO4 = 137 ml/1000 * 0.230 M = 0.03151 moles of KMnO4
From the reaction equation;
2 moles of permanganate reacts with 5 moles of H2O2
0.03151 moles of permanganate reacts with 0.03151 moles * 5/2 = 0.079 moles of H202
Mass of H2O2 reacted = 0.079 moles of H202 * 34 gmol-1 = 2.69 g
Hence % by mass of H2O2 in the sample = 2.69 g/35 g * 100 = 7.69%