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defon
2 years ago
10

The sale tax on an item is %6. Express the total cost, C, in terms of the price of the item, P.

Mathematics
1 answer:
skelet666 [1.2K]2 years ago
5 0
<h3>Answer: C = 1.06P</h3>

==========================================================

Explanation:

The sales tax is 6% of the price P

6% of P = 0.06P

Add on the original cost P to get P+0.06P = (1+0.06)P = 1.06P

The 1.06 indicates the final after tax cost is 106% of the original price.

You can think of it like 100% + 6% = 106% = 1.06

So that's how we end up with C = 1.06P

-----------

An example using actual numbers:

Let P = $100 be the initial cost before tax

6% of P = 0.06*P = 0.06*100 = 6 dollars is the tax

100+6 = 106 is the final cost

Note how C = 1.06P = 1.06*100 = 106

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A lathe is set to cut bars of steel into lengths of 6 cm. The lathe is considered to be in perfect adjustment if the average len
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Answer:

t=\frac{5.97-6}{\frac{0.4}{\sqrt{93}}}=-0.723    

E. -0.723

df=n-1=93-1=92  

p_v =2*P(t_{(92)}  

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Step-by-step explanation:

Information provided

\bar X=5.97 represent the sample mean for the length

s=0.4 represent the sample standard deviation

n=93 sample size  

\mu_o =6 represent the value that we want to test

\alpha=0.05 represent the significance level

t would represent the statistic  

p_v represent the p value for the test

System of hypothesis

We need to conduct a hypothesis in order to check if the lathe is in perfect adjustment (6cm), then the system of hypothesis would be:  

Null hypothesis:\mu = 6  

Alternative hypothesis:\mu \neq 6  

since we don't know the population deviation the statistic is:

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

Replacing in formula (1) we got:

t=\frac{5.97-6}{\frac{0.4}{\sqrt{93}}}=-0.723    

E. -0.723

P value

The degrees of freedom are given by:

df=n-1=93-1=92  

Since is a two tailed test the p value would be:  

p_v =2*P(t_{(92)}  

Since the p value is very high we don't have enough evidence to conclude that the true mean for the lengths is different from 6 cm.

5 0
3 years ago
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