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tangare [24]
2 years ago
9

Macromolecules aren't sticking with me. I need to memorize the basic and complex sugars.

Chemistry
2 answers:
likoan [24]2 years ago
8 0
This is a bio question not chemistry btw
givi [52]2 years ago
3 0

Answer:

Sugar is a food/spice. Macromolecules are the tiniest molecules if i was right. I do'nt know whether it is right. Happy to help...

Explanation:

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If nitrogen and hydrogen combine in a combustion reaction, what would the product of the reaction be?
kow [346]

Co2

Explanation:

CH4 (g) + 2 O2 (g) → CO2 (g) + 2 H2O (l)

4 0
3 years ago
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Which is more acidic black coffee or orange juice
EastWind [94]
Black coffee since it is a darker colour and has a heavier taste
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3 years ago
What are m and n in the rate law equation? Rate = k[A]^m[B]^n A. They are the coefficients obtained from the equation. B. They a
Sav [38]
The answer is A. The m and n are the coefficients obtained from the equation. And important thing is that the equation need to be balanced before using its coefficients.
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3 years ago
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The PH of a 0.1 M MCl (M is an unknown cation) was found to be 4.7. Write the net ionic equation for the hydrolysis of M and its
Serggg [28]

Answer:

6.25 X10^{-9} = Ka

Kb= \frac{10^{-14}}{6.25 X10^{-9}}= 1.6X10^{-6}

Explanation:

The ionic equation for the hydrolysis of the cation of the given salt will be:

M^{+} + H_{2}O ---> MOH + H^{+}

The expression for Ka will be:

Ka = \frac{[H^{+}][MOH]}{[M^{+}]}

As given that the concentration of the salt is 0.1 M and pH of solution = 4.7, we can determine the concentration of Hydrogen ions from the pH

pH = -log [H⁺]

[H⁺] = antilog(-pH) = antilog (-4.7) = 2 X 10⁻⁵ M = [MOH]

Let us calculate Ka from this,

Ka = {2.5X10^{-5}X2.5X10^{-5}}{0.1} = 6.25 X10^{-9}

The relation between Ka an Kb is

KaXKb =10⁻¹⁴

Kb= \frac{10^{-14}}{6.25 X10^{-9}}= 1.6X10^{-6}

6 0
3 years ago
What is the name given to the electrons in the highest occupied energy level of an atom? -anions -cations -valence electrons -or
Serhud [2]

Answer:

i know the answer the answer is valence electrons.

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3 years ago
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