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vlabodo [156]
2 years ago
11

Water, H2O, is a molecule made of oxygen and hydrogen. The bonds that hold water molecules together are due to shared __________

_, and known as covalent bonds. Question 12 options: electrons neutrons photons protons.
Chemistry
1 answer:
adell [148]2 years ago
5 0

Oxygen and hydrogen share electrons in the molecule of water to form covalent bonds.

<h3>What kinds of bonds exist?</h3>
  • Covalent bonds: These are formed between nonmetals and electrons by sharing electrons.
  • Ionic bonds: These are formed between metals, which lose electrons, and nonmetals, which gain electrons.
  • Metallic bonds: There are formed between metals. Electrons are delocalized in a cloud.

Water, H₂O, is a molecule made of 2 nonmetals: oxygen and hydrogen. The bonds that hold water molecules together are due to shared electrons, and known as covalent bonds.

Oxygen and hydrogen share electrons in the molecule of water to form covalent bonds.

Learn more about chemical bonds here: brainly.com/question/6071754

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A fruit-and-oatmeal bar contains 142 nutritional Calories. Convert this energy to calories
madreJ [45]

Answer:

a fruit and oatmeal bar contains 142000 calories.

A nutritional calorie, or kilocalorie, is equal to 1000 calories.

E = 142 kcal · 1000 cal/kcal.

E = 142 000 cal.

Calorie (cal), or small calorie, is the amount of energy needed to heat one gram of water by one degree Celsius.

One small calorie is approximately 4.2 joules.

A calorie is a unit of energy.

Explanation:

hope it helps  :)

4 0
3 years ago
What is the radius of a hydrogen atom whose electron is bound by 0.544 ev? express your answer with the appropriate units?
insens350 [35]
First, we need to calculate the principal quantum number n for this electron, using the equation:
E = (-13.60 eV) / (n x n)
where E is the energy that is used to bound the electron (here, E = - 0.544 eV).
- 0.544 eV = (-13.60 eV) / (n x n)
n x n = (- 13.60 eV) / (- 0.544 eV)
n x n = 25
n = 5

The orbital radius that is equal to the radius of a hydrogen atom is calculated using the equation:
r = 0.053 nm x n x n
r = 0.053 nm x 5 x 5
r = 0.053 nm x 25
r = 1.325 nm
6 0
3 years ago
Describe the ammonium ion, NH4+, and the sulfate ion, SO42-. What compounds would these ions form with potassium and fluoride io
frozen [14]
<span>Cations mix with anions, so you know NH4+ won't mix with K+ and SO4(2-) won't miix with F-. For the reason that NH4+ and F- together have single charges, they'll mix in a 1:1 ratio, NH4F. There's two charges on SO4(2-), so it'll need two K+ to mix with, K2SO4.</span>
6 0
4 years ago
Read 2 more answers
A welding tank of oxygen gas has a volume of 100. L. The oxygen in the tank is at a pressure of 95 atm and a temperature of 30.
Anuta_ua [19.1K]

Answer:

blah blah blah blah blah blah blah blah blah blah blah

5 0
3 years ago
Given 700 ml of oxygen at 7 ºC and 106.6 kPa pressure, what volume does it take at 27ºC and 66.6 kPa pressure
o-na [289]

Answer:

The volume is 1.2L

Explanation:

Initial volume (V1) = 700mL = 0.7L

Initial temperature (T1) = 7°C = (7 + 273.15)K = 280.15K

Initial pressure = 106.6kPa = 106600Pa

Final temperature (T2) = 27°C = (27 + 273.15)K = 300.15K

Final pressure (P2) = 66.6kPa = 66600Pa

Final volume (V2) = ?

To solve this question, we need to use combined gas equation which is a combination of Boyle's law, Charles Law and pressure law.

(P1 × V1) / T1 = (P2 × V2) / T2

solve for V2 by making it the subject of formula,

P1 × V1 × T2 = P2 × V2 × T1

V2 = (P1 × V1 × T2) / (P2 × T1)

V2 = (106600 × 0.7 × 300.15) / (66600 × 280.15)

V2 = 22397193 / 18657990

V2 = 1.2L

The final volume of the gas is 1.2L

6 0
3 years ago
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