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photoshop1234 [79]

2 years ago

11

What is the sum of the polynomials?

1 answer:

dmitriy555 [2]2 years ago

5 0

Answer:

Im pretty sure its D

Step-by-step explanation:

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The point (7, 8) is the solution of which of the following systems of equations?

Alex73 [517]

Option 4

<u>V</u><u>e</u><u>r</u><u>i</u><u>f</u><u>i</u><u>c</u><u>a</u><u>t</u><u>i</u><u>o</u><u>n</u><u>:</u><u>-</u>

$\\ \sf\longmapsto x-7y=-49$

$\\ \sf\longmapsto 7-7(8)=-49$

$\\ \sf\longmapsto 7-56=-49$

$\\ \sf\longmapsto -49=-49$

And

$\\ \sf\longmapsto 10x+9y=142$

$\\ \sf\longmapsto 10(7)+9(8)=142$

$\\ \sf\longmapsto 70+72=142$

$\\ \sf\longmapsto 142+142$

Hence verified

8 0

3 years ago

Read 2 more answers

Solve each equation mentally 1/7 × x = 1

Firlakuza [10]

Answer:

7

Step-by-step explanation:

4 0

3 years ago

Please help on 10 11 and 12

erastova [34]

Try multiplaying all sides

4 0

4 years ago

Find the simple interest earned on $2600 invested for 3 years at 12% per annum

Aleks04 [339]

Answer:

$936

Step-by-step explanation:

Simple interest is money you can earn by initially investing some money (a.k.a the principal). In return, a percentage (a.k.a the interest) of the initial money invested is added to the principal, this is what makes your initial investment grow.

The equation for simple interest is:

I = P x r x t

P = Principal, $2600

r = interest rate, 12%

t = time involved, 3 years

Fill in the values:

2600 × 0.12 × 3 = $936.00

5 0

3 years ago

Read 2 more answers

to arrive at 2000 liters of 60% saline solution the attendant has to mix a 90% and a 40% saline solution. How many liters of eac

CaHeK987 [17]

Answer:

<u>800 liters</u> of 90% saline solution and <u>1200 liters</u> of 40% saline solution should be used.

Step-by-step explanation:

Given:

At 2000 liters of 60% saline solution the attendant has to mix a 90% and a 40% saline solution.

Now, to find the number of liters of saline solution each should be used.

<u><em>Let the liters of 90% saline solution mix be </em></u> $x.$ <u><em /></u>

<u><em>And let the liters of 40% saline solution mix be</em></u> $y.$

So, the total number of liters:

$x+y=2000.$

$y=2000-x\ \ \ ....(1)$

Now, the total percentage of saline solution:

$90\%\ of\ x+40\%\ of\ y=60\%\ of\ 2000$

$\frac{90}{100}\times x+\frac{40}{100}\times y=\frac{60}{100}\times 2000$

$0.9x+0.4y=1200$

Substituting the value of $y$ from equation (1) we get:

$0.9x+0.4(2000-x)=1200$

$0.9x+800-0.4x=1200$

$0.5x+800=1200$

Subtracting both sides by 800 we get:

$0.5x=400$

Dividing both sides by 0.5 we get:

$x=800.$

<u>The liters of 90% saline solution mix = 800.</u>

Now, substituting the value of $x$ in equation (1) to get the liters of 40% saline solution:

$y=2000-x$

$y=2000-800$

$y=1200.$

<u>Thus, the liters of 40% saline solution = 1200.</u>

Therefore, 800 liters of 90% saline solution and 1200 liters of 40% saline solution should be used.

8 0

4 years ago