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andreyandreev [35.5K]
2 years ago
15

Please Help Will Mark Brainliest!!!

Chemistry
2 answers:
____ [38]2 years ago
7 0

The temperatures of the gases will not be equal.

  • The ideal gas law specifies the mechanical behavior of ideal gases. It is capable of calculating the volume of gases produced or consumed.
  • In chemical equations, this equation is widely used to convert between volumes and molar quantities.
  • The ideal gas law states that the pressure, temperature, and volume of gas are related to each other

PV=nRT

∵V is the same for both

∴T= same for both.

When n increases, T decreases, so, n is 1 for hydrogen gas and 0.5 for  oxygen gas ,implying that oxygen gas will have more temperature than hydrogen gas since its number of moles are lower than hydrogen gas.

Learn more:

brainly.com/question/1063475

bazaltina [42]2 years ago
6 0

Answer:

The ideal gas law specifies the mechanical behavior of ideal gases. It is capable of calculating the volume of gases produced or consumed.

In chemical equations, these equations are widely used to convert between volumes and molar quantities.

Use ideal gas law

Therefore

is the same for both So, = same for both.

When n increases, T decreases, so, n is 1 for and 0.5 for , implying that is hotter.

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Determine how many moles of CO2 are required to produce 11.0 mol of glucose,
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Determine how many moles of CO2 are required to produce 11.0 mol of glucose,

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3 years ago
A chemist prepares a solution of copper(II) sulfate CuSO4 by measuring out 31.μmol of copper(II) sulfate into a 150.mL volumetri
baherus [9]

Answer:

The concentration of the copper (II) sulfate solution is 2.06 * 10^2 μmol/L or 2.06 * 10^2 μM

Explanation:

The concentration of a solution is the amount of solute dissolved in a given volume of solution. In this case, the concentration of the copper(II) sulfate solution in micromoles per liter (symbol ) is the number of micromoles of copper(II) sulfate dissolved in each liter of solution. To calculate the micromoles of copper(II) sulfate dissolved in each liter of solution you must divide the total micromoles of solute by the number of liters of solution.

Here's that idea written as a formula: c= n/V

where c stands for concentration, n stands for the total micromoles of copper (II) sulfate and V stands for the total volume of the solution.

You're not given the volume of the solution in liters, but rather in milliliters. You can convert milliliters to liters with a unit ratio: V= 150. mL * 10^-3 L/ 1 mL = 0.150 L

Next, plug in μmol and liters into the formula to divide the total micromoles of solute by the number of liters of solution: c= 31 μmol/0.150 L = 206.66 μmol/L

Convert this number into scientific notation: 2.06 * 10^2 μmol/L or 2.06 * 10^2 μM

3 0
2 years ago
Urgent please help me!!!
nikitadnepr [17]

Explanation:

A. lithium hydroxide =LiOH

B. sodium cyanide =NaCN

C. Magnesium nitrate = Mg(NO3)2

D. Barium sulfate = BaSO4

E. Aluminum nitride = AlN

F. Potassium phosphate = KH2PO4

G. Ammonium bromide = NH4Br

H.Calcium carbonate = CaCO3

5 0
3 years ago
If a sample of oxygen gas originally at from 171.4 K has its temperature increased to 288.4 K and
julia-pushkina [17]

Answer:

V₂ = 0.95 L

Explanation:

Given data:

Initial temperature of gas = 171.4 K

Final temperature of gas = 288.4 K

Final volume = 1.6 L

Initial volume = ?

Solution:

The given problem will be solve through the Charles Law.

According to this law, The volume of given amount of a gas is directly proportional to its temperature at constant number of moles and pressure.

Mathematical expression:

V₁/T₁ = V₂/T₂

V₁ = Initial volume

T₁ = Initial temperature

V₂ = Final volume  

T₂ = Final temperature

Now we will put the values in formula.

V₁/T₁ = V₂/T₂

V₁ = V₂T₁ /T₂

V₂ = 1.6 L × 171.4 K / 288.4 k

V₂ = 274.24 L.K / 288.4 K

V₂ = 0.95 L

6 0
3 years ago
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