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2 years ago

Please Help Will Mark Brainliest!!!

Chemistry

2 answers:

____ [38]2 years ago

7 0

The temperatures of the gases will not be equal.

The ideal gas law specifies the mechanical behavior of ideal gases. It is capable of calculating the volume of gases produced or consumed.
In chemical equations, this equation is widely used to convert between volumes and molar quantities.
The ideal gas law states that the pressure, temperature, and volume of gas are related to each other

$PV=nRT$

∵V is the same for both

∴T= same for both.

When n increases, T decreases, so, n is 1 for hydrogen gas and 0.5 for oxygen gas ,implying that oxygen gas will have more temperature than hydrogen gas since its number of moles are lower than hydrogen gas.

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bazaltina [42]2 years ago

6 0

Answer:

The ideal gas law specifies the mechanical behavior of ideal gases. It is capable of calculating the volume of gases produced or consumed.

In chemical equations, these equations are widely used to convert between volumes and molar quantities.

Use ideal gas law

Therefore

is the same for both So, = same for both.

When n increases, T decreases, so, n is 1 for and 0.5 for , implying that is hotter.

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5000kg of ammonium nitrate per square kilometer of cornfield per year. how much nitric acid would be needed to make the fertiliz

Serggg [28]

$NH_3+HNO_3-> NH_4NO_3$

1 mole of nitric acid produce 1 mole of ammonium nitrate.

moles in 5000 kg of ammonium nitrate :

$n=\dfrac{5000\times 1000}{80}\\\\n=62500\ moles$ ( molecular mass of ammonium nitrate is 80 gm/mol )

So, number of moles of nitric acid required are also 62500 moles.

Mass of 62500 moles of nitric acid :

$mass = 62500\times 63 \\\\mass = 3937500\ gram\\\\mass = 393.75\ kg$

Hence, this is the required solution.

5 0

2 years ago

In thermodynamics, we determine the spontaneity of a reaction by the sign of ΔG. In electrochemistry, spontaneity is determined

faltersainse [42]

Answer:

For A: The standard cell potential of the reaction is 4.4 V

For B: The standard Gibbs free energy of the reaction is $-8.50\times 10^5J$

For C: The reaction is spontaneous as written.

Explanation:

For A:

The given chemical reaction follows:

$2Li(s)+Cl_2(g)\rightarrow 2Li^+(aq.)+2Cl^-(aq.)$

The given half reaction follows:

Oxidation half reaction: $Li(s)\rightarrow Li^+(aq.)+e^-;E^o_{Li^+/Li}=-3.04V$ ( × 2)

Reduction half reaction: $Cl_2(g)+2e^-\rightarrow 2Cl^-(aq.);E^o_{Cl_2/2Cl^-}=+1.36V$

The substance having highest positive $E^o$ potential will always get reduced and will undergo reduction reaction.

Here, chlorine will undergo reduction reaction will get reduced.

Substance getting oxidized always act as anode and the one getting reduced always act as cathode.

To calculate the $E^o_{cell}$ of the reaction, we use the equation:

$E^o_{cell}=E^o_{cathode}-E^o_{anode}$

$E^o_{cell}=1.36-(-3.04)=4.4V$

Hence, the standard cell potential of the reaction is 4.4 V

For B:

Relationship between standard Gibbs free energy and standard electrode potential follows:

$\Delta G^o=-nFE^o_{cell}$

where,

n = number of electrons transferred = $2mol\text{ e}^-$

F = Faradays constant = $96500J/V.mol\text{ e}^-$

$E^o_{cell}$ = standard cell potential = 4.4 V

Putting values in above equation, we get:

$\Delta G^o=-2\times 96500\times 4.4=-849200J=-8.50\times 10^5J$

Hence, the standard Gibbs free energy of the reaction is $-8.50\times 10^5J$

For C:

For a reaction to be spontaneous, the standard Gibbs free energy change of the reaction must be negative.

From above, the standard Gibbs free energy change of the reaction is coming out to be negative.

Hence, the reaction is spontaneous as written.

7 0

3 years ago

Hi! I really really need help roght now please help me and if u put whatever in the chas as in just to get points i will ban you

dolphi86 [110]

The correct order given below shows the changes that occurs in a mice population in response to changes in their environment:

The population of mice is in an environment with many black rocks
Mice with black for are more likely to survive and reproduce than mice with brown fur
After many generations, most of the mice in the population have black fur
A sandstorm covers most of the population's environment with brown sand
Mice with black fur are less likely to survive and reproduce than mice with brown fur
After many generations, most of the mice in the population have brown fur

<h3>What is the correct order for natural selection in the desert environment given?</h3>

Based on the process of natural selection due to envrionmental pressures, the population of the mice in the desert changes as follows before and after the environmental change:

The population of mice is in an environment with many black rocks
Mice with black for are more likely to survive and reproduce than mice with brown fur
After many generations, most of the mice in the population have black fur
A sandstorm covers most of the population's environment with brown sand
Mice with black fur are less likely to survive and reproduce than mice with brown fur
After many generations, most of the mice in the population have brown fur

Therefore, the correct order shows the changes that occurs in a mice population in response to changes in their environment.

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8 0

2 years ago

Suppose 180 ml of 3.52x10^-4 M NaOH is mixed with 220 mL of 2.47x10^-4 M MgCl2.

velikii [3]

When in water, MgCl2 dissociates into magnesium ions and Cl- ions and NaOH into Na and OH ions. The equation is as follows:

MgCl2 = Mg2+ + 2Cl-
NaOH = Na+ + OH-

The initial concentrations are as follows:

[Mg2+] = .220( 2.47x10^-4) / .220+.180 = 1.36x10^-4 M Mg2+
[OH-] = .180 (3.52x10^-4) / .220+.180 = 1.58x10^-4 M OH-

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3 years ago

During the daytime, wind blows off of the __________________ because that material takes ___________ time to get warm, creating

Butoxors [25]

Answer: sea, more

I hope this helps

5 0

2 years ago