Answer:
0.000237mL
Explanation:
0.237 x 10^-6L = 0.000000237L = mL
0.000237mL
For number 22. The answer is c. To find this look at the numbers before each compound O2 has no number which means 1, while CO2 has a 2 in front
Answer:
<u> </u><u>85.952 ml</u>
needed to titrate the excess complexing reagent .
Explanation:
Lets calculate
After addition of 80 ml of EDTA the solution becomes = 20 + 70 = 90 ml
As the number of moles of
=
=
=0.01172
Molarity = 
=
=0.000586 moles
Excess of EDTA = concentration of EDTA - concentration of CoSO4
= 0.009005 - 0.000586
= 0.008419 M
As M1V1 ( Excess of EDTA ) = M2V2 


V2 =85.952 ml
Therefore , <u>85.952 ml </u>
needed to titrate the excess complexing reagent .
Answer:
Los parámetros dados del movimiento son;
La velocidad con la que el atleta se dirige hacia la línea de salida = 6 m / s
El punto en el que se inicia el cronómetro = marca de 100 m
La ecuación para la distancia recorrida, 's', se da como sigue;
s = 6 m / s × t
La distancia total recorrida, d = 100 + s
∴ d = 100 + 6·t
Los gráficos de las ecuaciones se crean con Microsoft Excel y se presentan de la siguiente manera;
Explanation: