The concentration of solids is constant and usually taken equal to unity ,therefore it does not appear in the equilibrium constant ,so adding or removing solid has no effect. So According to Le Chatelet's Principle the amount of solid reactant or product present does not have an impact on the equilibrium
What is Le Chatelet's Principle ?
The position of the equilibrium in a chemical reaction can be predicted with the aid of Le Chatelet's Principle in response to changes in temperature, concentration, or pressure. This is crucial, especially for industrial applications where it's crucial to predict and maximize yields.
According to Le Châtelet's principle, if a dynamic equilibrium is upset by changing the conditions, the equilibrium position will move to compensate for the change and restore the equilibrium.
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Answer:
ΔG° = - RTLnK is used to find the standard cell potential given the equilibrium constant
Explanation:
for an ideal disolution:
⇒ ΔG = RT∑ni LnXi
∴ ΔG = ( μi - μi*)ni
∴ μ : chemical potential
∴ μ*: chem. potential of the pure component at T and P.
⇒ ΔG = μi - μi* = RT LnXi
for a equilibrium reaction:
⇒ ∑ νi*μi = 0
⇒ ΔGr = ΔG°+ RT Ln Kx = 0
⇒ ΔG° = - RT LnKx
Answer:
Isotopes of an element have same number of protons but different number of neutrons. Which means isotopes of an element have same atomic number but different mass number.
The chemical property of an element is determined by the number of electrons. And as all the isotopes have same number of electrons, they have same chemical properties.
Thus as isotopes of an element have same atomic number , they have same number of electrons and protons. As they have different mass number, the number of neutrons will be different. Hydrogen has three isotopes , 
, 
and 
. Thus has no neutron.
Answer: 50. 4g
Explanation:
First calculate number of moles of aluminium in 38.8g
Moles = 38.8g/ 26.982mol/g
= 1.44mol
By looking at the balance equation you can see that 4 moles of aluminium produce 2 moles of aluminium oxide.
4 = 2
1.4 = x
Find the value of x
x= (1.4×2)/4= 0.72 mol
0.72 moles of aluminium oxide are produced from 38.8g of aluminium
Now find the mass of aluminium produced.
Mass = moles × molar mass
= 0.72mol × 69.93 mol/g
= 50.4g
