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cluponka [151]
3 years ago
14

Which of the following statements is the most accurate? A. Energy transfers are never 100% efficient. B. Energy transfer is comp

letely efficient. C. Energy cannot be transferred to other forms. D. Energy transfers can be used to create perpetual-motion machines.
Chemistry
2 answers:
qaws [65]3 years ago
6 0
I'd say it's A because while the energy cannot be lost, it can not be 100% efficient because if it was we wouldn't have to worry about energy.
Olegator [25]3 years ago
5 0

Answer:

A. Energy transfers are never 100% efficient

Explanation:

According to the  first law of thermodynamics energy can neither be created nor destroyed but it can be converted from one form to another. According to the second law of thermodynamics transfer of energy is never 100% efficient in a machine. There is always loss of energy due to wear and tear of the machinery.

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Predict whether the changes in enthalpy, entropy, and free energy will be positive or negative for the freezing of water, and ex
Dafna11 [192]

Answer:

Explanation:

The total energy or intrinsic energy of a system is called the enthalpy. In thermochemistry, we have two types of enthalpy changes which are:

  • Exothermic changes
  • Endothermic changes

For the freezing of water, the enthalpy change is an exothermic one. Exothermic changes are designated as negative. In this chemical change, heat is liberated to the surroundings and this leaves the environment at a much higher temperature. In freezing, the enviroment gains more heat as the material begins to cool to lower temperature.

Entropy is the degree of randomness or disorderliness of a system. When a phase change occurs from liquid to solid, freezing takes place. Such a change increases the orderliness of a system and entropy diminishes. Here, entropy is negative.

The free energy is a measure of the energy a system that does useful work. Free energy depends on enthalpy, entropy and temperature of a system. For phase changes such as freezing of water, the value of free energy change is 0.

For this process, an increases in temperature makes it non-spontaneous. Increasing temperature would alter the course of the reaction and makes it exothermic. For entropy, increasing temperature would increase entropy and therefore, the reaction would not be feasible.

Temperature would mostly affect the free energy. An increase in temperature would increase the value of entropy change and the reaction would not be spontaneous. With falling temperature value, the reaction becomes more spontaneous and favored.

8 0
3 years ago
Choose the example that is a protein:<br> •bread<br> •enzyme<br> •ORNA<br> •sugar
taurus [48]

Answer:

I think bread is the answer

4 0
4 years ago
0.378g grams of a compound is made up of 0.273g of Mg and 0.105g nitrogen. Find its empirical formula.
Harrizon [31]

Answer:

The empirical formula of the compound is Mg_3N_2.

Explanation:

Mass of magnesium in compound = 0.273 g

Mass of nitrogen in the compound = 0.105 g

Moles of magnesium =\frac{0.273 g}{24.305 g/mol}=0.0112 mol

Moles of nitrogen = \frac{0.105 g}{14.0067 g/mol}=0.00750 mol

Form empirical formula divides the lowest value of moles of an element present with all the moles of elements present.

Magnesium =\frac{0.0112 mol}{0.00750 mol}=1.5

Nitrogen =\frac{0.00750mol}{0.00750 mol}=1

The empirical formula of a compound:

Mg_{1.5}N_1=Mg_{\frac{15}{10}}N_1=Mg_{15}N_{10}=Mg_3N_2

The empirical formula of the compound is Mg_3N_2.

3 0
3 years ago
If the value of Kc for the reaction is 2.50, what are the equilibrium concentrations if the reaction mixture was initially 0.500
ratelena [41]

<u>Answer:</u> The equilibrium concentration of sulfur dioxide, nitrogen dioxide, sulfur trioxide, nitrogen monoxide is 0.196 M, 0.196 M, 0.309 M and 0.309 M respectively.

<u>Explanation:</u>

We are given:

Initial concentration of sulfur dioxide = 0.500 M

Initial concentration of nitrogen dioxide = 0.500 M

Initial concentration of sulfur trioxide = 0.00500 M

Initial concentration of nitrogen monoxide = 0.00500 M

The chemical reaction follows:

                         SO_2+NO_2\rightleftharpoons SO_3+NO

<u>Initial:</u>             0.500  0.500      0.005   0.005

<u>At eqllm:</u>      0.500-x  0.500-x   0.005+x  0.005+x

The expression of equilibrium constant for the above reaction follows:

K_c=\frac{[SO_3][NO]}{[SO_2][NO_2]}

We are given:

K_c=2.50

Putting values in above equation, we get:

2.50=\frac{(0.005+x)\times (0.005+x)}{(0.500-x)\times (0.500-x)}\\\\x=0.304,1.37

Neglecting the value of x = 1.37, because change cannot be greater than the initial concentration

So, equilibrium concentration of sulfur dioxide = (0.500-x)=(0.500-0.304)=0.196M

Equilibrium concentration of nitrogen dioxide = (0.500-x)=(0.500-0.304)=0.196M

Equilibrium concentration of sulfur trioxide = (0.00500+x)=(0.00500+0.304)=0.309M

Equilibrium concentration of nitrogen monoxide = (0.00500+x)=(0.00500+0.304)=0.309M

Hence, the equilibrium concentration of sulfur dioxide, nitrogen dioxide, sulfur trioxide, nitrogen monoxide is 0.196 M, 0.196 M, 0.309 M and 0.309 M respectively.

4 0
3 years ago
Which of the following is true regarding the transition elements?
e-lub [12.9K]
Pls complete your question
8 0
4 years ago
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