Answer:
m<AIR = 90 deg
Step-by-step explanation:
I assume the problem contains an error, and that AR is a diameter, not AC.
Look at the diameter of the circle, AR. It passes through the center of the circle, C. You can think of the two radii of the circle, CR and CA, as sides of angle RCA. Since AR is a diameter, and AR is a segment which is part of line AR, rays CR and CA are sides of an angle that lie on a line. That makes the measure of angle RCA 180 deg. Angle RCA is a central angle of circle C since its vertex is the center of the circle.
Angle AIR is an inscribed angle in circle C since its vertex is on the circle itself. If an inscribed angle and a central angle intercept the circle at the same two points, then the measure of the inscribed angle is half the measure of the central angle.
m<AIR = (1/2)m<RCA = (1/2) * 180 = 90
m<AIR = 90 deg
Answer:
a) Exterior Angle Theorem
b) x = 109°
Step-by-step explanation:
For a, you can thank the Exterior Angle Theorem. Since the angles of a triangle equal 180°, we can figure out what the third interior angle's measurement is, then subtract that from 180 to get the exterior angle's measure. Since the two angles labeled (64° and 45°) will make an obtuse angle, then the third interior is an acute angle. Add 64 and 45 to get the exterior angle's measurement of 109 degrees. That would mean the third interior angle's measurement would be 71 degrees. 64 + 45 + 71 = 180, so this is true.
(I had used the HSEAT to explain this.)
Answer:
(y+9)(y-1)
Step-by-step explanation:
y^2+9y-8y-9
y(y+9)-1(y+9)
(y+9)(y-1)
With replacement:
P(C,V)=(12/40)(28/40)
P(C,V)=336/1600
P(C,V)=21/100