The difference between the baseband and the broadband connection is made with the transmission of signal over the frequency.
<h3 /><h3>What is data transmission?</h3>
The data transmission is given as the transfer of the data from one digital device to another. The transmission can take place with the baseband transmission and the broadband transmission.
The major difference between the two transmissions is that the baseband utilizes a complete frequency for transmission of signal, while the transmission with the broadband is made with multiple signals over multiple frequencies.
Learn more about broadband signals, here:
brainly.com/question/19204110
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Answer:
(Option C)
Explanation:
The initial and final speed of the toolbox is found by means of the Principle of Energy Conservation:
![\frac{1}{2}\cdot m \cdot v_{in}^{2} = m \cdot g \cdot h_{in}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%5Ccdot%20m%20%5Ccdot%20v_%7Bin%7D%5E%7B2%7D%20%3D%20m%20%5Ccdot%20g%20%5Ccdot%20h_%7Bin%7D)
![v_{in} = \sqrt{2\cdot g \cdot h_{in}}](https://tex.z-dn.net/?f=v_%7Bin%7D%20%3D%20%5Csqrt%7B2%5Ccdot%20g%20%5Ccdot%20h_%7Bin%7D%7D)
![v_{in} = \sqrt{2\cdot \left(9.807\,\frac{m}{s^{2}} \right)\cdot (0.2\,m)}](https://tex.z-dn.net/?f=v_%7Bin%7D%20%3D%20%5Csqrt%7B2%5Ccdot%20%5Cleft%289.807%5C%2C%5Cfrac%7Bm%7D%7Bs%5E%7B2%7D%7D%20%5Cright%29%5Ccdot%20%280.2%5C%2Cm%29%7D)
![v_{in}\approx 1.981\,\frac{m}{s}](https://tex.z-dn.net/?f=v_%7Bin%7D%5Capprox%201.981%5C%2C%5Cfrac%7Bm%7D%7Bs%7D)
![v_{out} = \sqrt{2\cdot g \cdot h_{out}}](https://tex.z-dn.net/?f=v_%7Bout%7D%20%3D%20%5Csqrt%7B2%5Ccdot%20g%20%5Ccdot%20h_%7Bout%7D%7D)
![v_{out} = \sqrt{2\cdot \left(9.807\,\frac{m}{s^{2}} \right)\cdot (0.05\,m)}](https://tex.z-dn.net/?f=v_%7Bout%7D%20%3D%20%5Csqrt%7B2%5Ccdot%20%5Cleft%289.807%5C%2C%5Cfrac%7Bm%7D%7Bs%5E%7B2%7D%7D%20%5Cright%29%5Ccdot%20%280.05%5C%2Cm%29%7D)
![v_{out}\approx 0.99\,\frac{m}{s}](https://tex.z-dn.net/?f=v_%7Bout%7D%5Capprox%200.99%5C%2C%5Cfrac%7Bm%7D%7Bs%7D)
The impact is calculated by means of the Principle of Momentum Conservation and the Impulse Theorem:
![Imp = m\cdot(v_{out}-v_{in})](https://tex.z-dn.net/?f=Imp%20%3D%20m%5Ccdot%28v_%7Bout%7D-v_%7Bin%7D%29)
![Imp = (12\,kg)\cdot \left[0.99\,\frac{m}{s} - (-1.981\,\frac{m}{s})\right]](https://tex.z-dn.net/?f=Imp%20%3D%20%2812%5C%2Ckg%29%5Ccdot%20%5Cleft%5B0.99%5C%2C%5Cfrac%7Bm%7D%7Bs%7D%20-%20%28-1.981%5C%2C%5Cfrac%7Bm%7D%7Bs%7D%29%5Cright%5D)
![Imp = 35.652\,N\cdot s](https://tex.z-dn.net/?f=Imp%20%3D%2035.652%5C%2CN%5Ccdot%20s)
Answer:
The percent elongation in the length of the specimen is 42%
Explanation:
Given that:
The gage length of the original test specimen
= 50 mm
The final gage length
= 71 mm
The area = 206 mm²
maximum load = 162,699 N
To determine the percent elongation in %, we use the formula:
![\%EL = \dfrac{L_f-L_o}{L_o}\times 100](https://tex.z-dn.net/?f=%5C%25EL%20%3D%20%5Cdfrac%7BL_f-L_o%7D%7BL_o%7D%5Ctimes%20100)
![\%EL = \dfrac{71 \ mm-50 \ mm}{50 \ mm}\times 100](https://tex.z-dn.net/?f=%5C%25EL%20%3D%20%5Cdfrac%7B71%20%5C%20mm-50%20%5C%20mm%7D%7B50%20%5C%20mm%7D%5Ctimes%20100)
![\%EL = \dfrac{21 mm}{50 \ mm}\times 100](https://tex.z-dn.net/?f=%5C%25EL%20%3D%20%5Cdfrac%7B21%20mm%7D%7B50%20%5C%20mm%7D%5Ctimes%20100)
![\%EL = 0.42 \times 100](https://tex.z-dn.net/?f=%5C%25EL%20%3D%200.42%20%5Ctimes%20100)
![\mathbf{\%EL = 42 \%}](https://tex.z-dn.net/?f=%5Cmathbf%7B%5C%25EL%20%3D%2042%20%5C%25%7D)
The percent elongation in the length of the specimen is 42%
Answer: 2A
Explanation: Current, i in amperes, A can be got by dividing the charge, Q by time, t
Therefore
i = Q/t
i = 60/30
i = 2A
Answer:
MUDA MUDA A certain vehicle loses 3.5% of its value each year. If the vehicle has an initial value of $11,168, construct a model that represents the value of the vehicle after a certain number of years. Use your model to compute the value of the vehicle at the end of 6 years.
Explanation: