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weeeeeb [17]
3 years ago
13

The “Sun-Star” Company has purchased new office furniture for their offices at a retail price of $100,000. An additional $12,000 h

as been charged for insurance, shipping, and handling. The company expects to use the furniture for 10 years (useful life = 10 years) and then sell it at a salvage (market) value of $8,000. Use the SL method of depreciation to answer these questions. a. What is the depreciation during the second year? b. What is the BV of the asset at the end of the first year? c. What is the BV of the asset after eight years?
Engineering
1 answer:
Zinaida [17]3 years ago
4 0

Based on the cost of the furniture, the following are true:

  • a. $10,400.
  • b. $93,600
  • c. $20,800

<h3>Depreciation in second year</h3>

Depreciation per year = (Cost of furniture - Salvage value) / Useful life

Cost will include both the purchase price and the charge for insurance and shipping.

= (100,000 + 12,000 - 8,000) / 10

= $10,400

<h3>BV at end of first year</h3>

= Cost - Depreciation

= 104,000 - 10,400

= $93,600

<h3>BV after 8 years </h3>

= Cost - (Depreciation x 8 years )

= 104,000 - (10,400 x 8)

= $20,800

In conclusion, depreciation is $10,400 per year.

Find out more about SL depreciation at brainly.com/question/13734742.

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As the complete question is not given the complete question is found online and is attached herewith.

By applying KCL at node 1

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Also

V_{\Delta}=1K*i_y

Now applying KVL on loop 1 as indicated in the attached figure

1K*i_y+5K(i_y-i_z)+3K*i_x=0\\3i_x+6 i_y-5i_z=0

Similarly for loop 2

2V_{\Delta}+5K(i_z-i_y)=0\\2*1K*i_y+5K(i_z-i_y)=0\\2K*i_y+5K(i_z-i_y)=0\\3i_y-5i_z=0

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V_{\Delta}=1K*i_y\\V_{\Delta}=1K*-25 mA\\V_{\Delta}=-25 V

The values of i_x,i_y and i_z as 25 mA, -25 mA and 15 mA while that of V_Δ is -25 V

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