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otez555 [7]
3 years ago
15

4. A 62.0-kg person, standing on the diving board, dives straight down into the water. Just before striking the water, her speed

is 5.50 m/s. At a time of 1.65 s after she enters the water, her speed is reduced to 1.10 m/s. What is the net average force (magnitude and direction) that acts on her when she is in the water?
Physics
1 answer:
Alekssandra [29.7K]3 years ago
7 0

To solve this problem it is necessary to apply the concepts related to the Moment. The moment in terms of the Force and the time can be expressed as

\Delta P = F\Delta t

F = Force

\Delta t = Time

At the same time the moment can be expressed in terms of mass and velocity, mathematically it can be given as

P = m \Delta v

Where

m = Mass

\Delta v = Change in velocity

Our values are given as

\Delta t=1.65s

By equating the two equations we can find the Force,

F\Delta t = m\Delta v

F = \frac{m\Delta v}{\Delta t}

F = \frac{62(1.1-5.5)}{1.65}

Therefore, the net average force will be:

F = - 165N

The negative symbol indicates that the direction of the force is upwards.

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B)A man walks 95 km, East, then 55 km, north. Calculate his RESULTANT
Varvara68 [4.7K]

The resultant displacement of the man is 109.77 km in the direction N60°E.

<h3>Displacement</h3>

Displacement is the distance travelled in a specified direction.

To calculate displacement, the straight line from starting point to end point of travel is taken and calculated.

<h3>Resultant displacement of the man </h3>

In the example above, a man walks 95 km, East, then 55 km, north.

The two distances form a right-angled triangle with two sides 95 and 55 units. The hypotenuse gives the resultant displacement, D.

Using Pythagoras rule:

D^2 = 95^2 + 55^2

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D = 109.77

Thus, the resultant displacement is 109.77 km

To calculate the direction:

Let the direction be y

y + x = 90°

tan x = 55/95

tanx x = 0.578

x = 30°

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y = 60°

Therefore, the resultant displacement of the man is 109.77 km in the direction N60°E.

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2 years ago
The 8 kg block is then released and accelerates to the right, toward the 2 kg block. The surface is rough and the coefficient of
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Answer:

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As the energy in the system is conserved we have

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