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3 years ago

1. An astronaut is getting ready to explore. If his mass is 60 kg, what is his weight on Earth?

Physics

2 answers:

Dima020 [189]3 years ago

8 0

Weight= mg
Weight= (60 kg) (9.8 m/s2)
Weight= 588

kifflom [539]3 years ago

3 0

Answer:

<h3>The mass of an object is the same on Earth, in orbit, or on the surface of the Moon. ... 1N=1kg ⋅m/s2. 1 N = 1 kg · m/s 2 . ... The gravitational force on a mass is its weight. ... </h3>

Explanation:

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Determine the force of gravitational attraction between the Earth and the moon. Their masses are 5.98 x 1024 kg and 7.26 x 1022

Neporo4naja [7]

Answer:

$F =1.974 \times {10}^{ 20} N$

Explanation:

The formula for the force of attraction is given by

$F = \frac{Gm_1m_2}{ {r}^{2} }$

where,

F= Force

G= universal gravitational constant

$m_1 and \: m_2$

are the masses of the two bodies.

r= the distance between the two bodies.

Let the mass of the Earth= $m_1$ and that of the moon= $m_2$ .

From the question,

$m_1= 5.98\times {10}^{24} kg$

$m_2= 7.26 \times {10}^{22} kg$ ,

$r= 3.83 \times10^8 m$

We substitute these values into the equation,Assuming,

$G = 6.67 \times {10}^{ - 11} N m^2 kg^{-2}$

This implies that,

$F = \frac{6.67 \times {10}^{ - 11 } \times 5.98 \times {10}^{24} \times 7.26 \times {10}^{22}}{ ({3.83 \times 10}^{8})^2}$

$F = 1.974 \times {10}^{20} N$

3 0

4 years ago

A meter stick is held vertically with one end on the floor and is then allowed to fall. Find the speed of the other end just bef

stich3 [128]

Answer:

v = 7.67 m/s for L= 1m

Explanation:

Let's use the conservation of mechanical energy, at the highest point and the lowest point

Initial. Vertical ruler

Em₀ = mg h

Final. Just before touching the floor

$Em_{f}$ = K = ½ I w²

Em₀ = $Em_{f}$

m g h = ½ I w²

The moment of inertia of a ruler that turns on one end is

I = 1/3 m L²

Let's replace

m g h = ½ (1/3 m L²) w²2

g h = 1/6 L² w²

They ask for the speed of the end so the height h is equal to the length of the ruler

g L = 1/6 L² w²

The linear and angular variables are related

v = w r

w = v / r

In this case the point of interest a in strangers r = L

g L = 1/6 L² v² / L²

v = √ 6 g L

Let's calculate

Assume that the length of the meter is L = 1 m

v = √ (6 9.8 1)

v = 7.67 m/s

7 0

3 years ago