Answer:
The term rotational and irrotational flow is associated withe the flow of particles in fluid.
The common example of irrrotational flow can be seen on the carriages of the Ferris wheel (giant wheel).
Explanation:
- If the fluid is rotating along its axis with the streamline flow of its particles,then this type of flow is rotational flow.
- Similarly if fluid particles do not rotate along its axis while flowing in a stream line flow then it is considered as the irrotational flow.
- In majority, if the flow of fluid is viscid then it is rotational.
- Fluid in a rotating cylinder is an example of rotating flow.
In order to make his measurements for determining the Earth-Sun distance, Aristarchus waited for the Moon's phase to be exactly half full while the Sun was still visible in the sky. For this reason, he chose the time of a half (quarter) moon.
<h3 /><h3>How did Aristarchus calculate the distance to the Sun?</h3>
It was now possible for another Greek astronomer, Aristarchus, to attempt to determine the Earth's distance from the Sun after learning the distance to the Moon. Aristarchus discovered that the Moon, the Earth, and the Sun formed a right triangle when they were all equally illuminated. Now that he was aware of the distance between the Earth and the Moon, all he needed to know to calculate the Sun's distance was the current angle between the Moon and the Sun. It was a wonderful argument that was weakened by scant evidence. Aristarchus calculated this angle to be 87 degrees using only his eyes, which was not far off from the actual number of 89.83 degrees. But when there are significant distances involved, even slight inaccuracies might suddenly become significant. His outcome was more than a thousand times off.
To know more about how Aristarchus calculate the distance to the Sun, visit:
brainly.com/question/26241069
#SPJ4
Answer:
1500 divided by 150(15m x 10m/s^2) = 10
Answer:
Explanation:
doubling the speed will have a greater impact on kinetic energy as KE is a product of mass and the square of velocity.
KE = ½mv²
Base KE = ½(0.005)2.0² = 0.01 J
doubling the mass
KE = ½(0.010)2.0² = 0.02 J
doubling the velocity
KE = ½(0.005)4.0² = 0.04 J
Answer:
The answer is a prism
Hope it helps...............
