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3 years ago

A measure of change in velocity in a measure of time is

1 answer:

8 0

$\\ \sf\Rrightarrow Acceleration=\dfrac{\Delta V}{t}[)tex]In simplified form[tex]\\ \sf\Rrightarrow Acceleration=\dfrac{dv}{dt}$

The rate of change of velocity with respect to time period is called acceleration.
SI units-m/s^2

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An ideal gas is brought through an isothermal compression process. The 5.00 mol of gas goes from an initial volume of 216.5×10−6

Lelechka [254]

Explanation:

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3 years ago

at a particular instant a hot air balloon is 100m in the air and decending at a constant speed of 2m/s at this exact instant a g

labwork [276]

<h2>She will find the ball at a horizontal distance of 86.4 m from landed location</h2>

Explanation:

Consider the vertical motion of ball

We have equation of motion s = ut + 0.5 at²

Initial velocity, u = 2 m/s

Acceleration, a = 9.81 m/s²

Displacement, s = 100 m

Substituting

s = ut + 0.5 at²

100 = 2 x t + 0.5 x 9.81 xt²

4.905t² + 2t - 100 = 0

t = 4.32 s or t = -4.72 s

After 4.32 seconds the ball reaches ground.

Now we need to find horizontal distance traveled by ball in 4.32 seconds.

We have equation of motion s = ut + 0.5 at²

Initial velocity, u = 20 m/s

Acceleration, a = 0 m/s²

Time, t = 4.32 s

Substituting

s = ut + 0.5 at²

s = 20 x 4.32 + 0.5 x 0 x 4.32²

s = 86.4 m

She will find the ball at a horizontal distance of 86.4 m from landed location

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4 years ago

Which one of the following is an example of a redox reaction?

arlik [135]

B: Rust on a bicycle -Apex

4 0

3 years ago

Read 2 more answers

A 5 meter long ladder leans against a wall. The bottom of the ladder slides away from the wall at the constant rate of 1 3 m/s.

Oksana_A [137]

Answer:9.75 m/s

Explanation:

Given

Length of ladder $(L)=5 m$

Foot the ladder is moving away with speed of $\frac{\mathrm{d} x}{\mathrm{d} t}=13 m/s$

From diagram

$x^2+y^2=L^2$ ------1

at $x=3$

$y^2=25-9=16$

$y=4 m$

Now differentiating equation 1 w.r.t time

$2x\frac{\mathrm{d} x}{\mathrm{d} t}+2y\frac{\mathrm{d} y}{\mathrm{d} t}=0$

$x\frac{\mathrm{d} x}{\mathrm{d} t}=-y\frac{\mathrm{d} y}{\mathrm{d} t}$

$3\times 13=-4\times \frac{\mathrm{d} y}{\mathrm{d} t}$

$\frac{\mathrm{d} y}{\mathrm{d} t}=-\frac{3\times 13}{4}=-9.75 m/s$

negative indicates distance is decreasing with time

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3 years ago

PLEASE HELP WITH THIS!

jok3333 [9.3K]

Answer: A

Explanation:

Parallel circuit. The source current is three times the current of a single bulb

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3 years ago