3 years ago

A measure of change in velocity in a measure of time is

1 answer:

8 0

$\\ \sf\Rrightarrow Acceleration=\dfrac{\Delta V}{t}[)tex]In simplified form[tex]\\ \sf\Rrightarrow Acceleration=\dfrac{dv}{dt}$

The rate of change of velocity with respect to time period is called acceleration.
SI units-m/s^2

You might be interested in

kramer

Answer:

60.2 J

Explanation:

Efficiency is the ratio of work out to work in.

e = Wout / Win

0.86 = Wout / 70 J

Wout = 60.2 J

5 0

3 years ago

Read 2 more answers

jill's car has a maximum acceleration of 8.7 miles per hour per second. how many seconds does it take her to acceleration from 0

amm1812

T = ?
v1 = 0mph
v2 = 60mph
a = 8.7mph/s

$a = \frac{v2 - v1}{t}
 \\ t = \frac{v2-v1}{a}
 \\ t = \frac{60mph - 0mph}{8.7mph/s}
 \\ t = 6.90s$

Therefore, it takes 6.90 seconds for Jill to accelerate from 0 to 60 miles per hour.

4 0

3 years ago

Ground-based radio telescopes can collect data from distant objects in space

Arada [10]

Answer is A. Because the telescope are use in night

4 0

3 years ago

Read 2 more answers

A student uses a spring loaded launcher to launch a marble vertically in the air. The mass of the marble is

GarryVolchara [31]

Answer:

Part a)

When spring compressed by 2 cm

H = 1.47 m

Part b)

When spring is compressed by 4 cm

H = 5.94 m

Explanation:

Part a)

As we know that the spring is compressed and released

so here spring potential energy is converted into gravitational potential energy at its maximum height

So we will have

$\frac{1}{2}kx^2 = mg(H + x)$

$0.5(220)(0.02)^2 = 0.003(9.81)(H + 0.02)$

so we have

$H = 1.47 m$

Part b)

Similarly when spring is compressed by 4 cm

then we have

$\frac{1}{2}kx^2 = mg(H + x)$

$0.5(220)(0.04)^2 = 0.003(9.81)(H + 0.04)$

so we have

$H = 5.94 m$

8 0

3 years ago

A motorcycle is moving at a constant velocity of 15 meters/second. Then it starts to accelerate and reaches a velocity of 24 met

Tanya [424]

option E

3m/s square

hope it helped u

6 0

3 years ago