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goldenfox [79]
3 years ago
10

A rock is suspended from a string, and it accelerates downward. Which one of the following statements is correct? Group of answe

r choices
a. The magnitude of the tension in the string is greater than the magnitude of the weight of the rock.
b. The magnitude of the tension in the string is independent of the magnitude of the rock's acceleration..
c. The magnitude of the tension in the string is equal to the magnitude of the weight of the rock.
d. The string pushes downward on the rock.
e. The magnitude of the tension in the string is less than the magnitude of the weight of the rock.
Physics
1 answer:
Tems11 [23]3 years ago
4 0

Answer:

a. The magnitude of the tension in the string is greater than the magnitude of the weight of the rock.

Explanation:

During the motion of the rock while it is in downward motion we can say

T - mg cos\theta = ma_c

since it is performing circular motion so we will have its acceleration towards its center

T = mgcos\theta + ma_c

a_c = \frac{v^2}{L}

T = mgcos\theta + \frac{mv^2}{L}

So at the lowest point of the path we can say

T = mg + \frac{mv^2}{L}

so correct answer is

a. The magnitude of the tension in the string is greater than the magnitude of the weight of the rock.

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8 0
3 years ago
A motorcycle is traveling up one side of a hill and down the other side. The crest of the hill is a circular arc with a radius o
Setler79 [48]

Answer:

21.8 m/s

Explanation:

At the top of the hill (crest), there are two forces acting on the motorcycle:

- The reaction force of the road, N (upward)

- The force of gravity, mg (downward)

Since the motorcycle is moving by circular motion, the resultant of these forces will give the centripetal force, so:

mg-N = m\frac{v^2}{r}

where the direction of the weight (mg) is equal to that of the centripetal force, and where

m is the mass of the cycle

g = 9.8 m/s^2 is the acceleration of gravity

v is the speed

r = 48.6 is the radius of the hill

The cycle loses contact with the road when the reaction force becomes zero:

N = 0

Substituting into the equation, we therefore find the maximum speed that is allowed for the cycle before losing constact:

mg = m\frac{v^2}{r}\\v=\sqrt{gr}=\sqrt{(9.8)(48.6)}=21.8 m/s

6 0
3 years ago
The slower the particles in a substance move,
swat32

Answer: particles move closer together

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3 0
3 years ago
One day, after pulling down your window shade, you notice that sunlight is passing through a pinhole in the shade and making a s
DedPeter [7]

Complete Question

One day, after pulling down your window shade, you notice that sunlight is passing through a pinhole in the shade and making a small patch of light on the far wall. Having recently studied optics in your physics class, you're not too surprised to see that the patch of light seems to be a circular diffraction pattern. It appears that the central maximum is about 2 cm across, and you estimate that the distance from the window shade to the wall is about 5 m.

Required:

Estimate the diameter of the pinhole.  

Answer:

The diameter is  d =0.000336 m

Explanation:

     From the question we are told that

            The central maxima is D= 2cm = \frac{2}{100} = 0.02m

            The distance from the window shade is L = 5m

     The  average wavelength of the  sun is mathematically evaluated as

                         \lambda_{ave } = \frac{\lambda_i  + \lambda_f}{2}

 Generally the visible light spectrum  has a wavelength  range  between  400 nm  to 700 nm  

        So  the initial wavelength of the sun is \lambda _i = 400nm

           and the final wavelength is  \lambda_f = 700nm

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                 \lambda_{sun} = \frac{400nm  +700nm}{2}

                        = 550nm

The diameter is evaluated as

              d = \frac{2.44 \lambda_{sun} L}{D}

substituting values

              d = \frac{2.44 * 550*10^{-9} * 5 }{0.02}

                d =0.000336 m

5 0
3 years ago
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Salsk061 [2.6K]

Answer:

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Explanation:

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