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Norma-Jean [14]
3 years ago
11

From the earth, the moon subtends an angle of approximately 0.5°. If the distance to the moon is approximately 240,000 miles, fi

nd an approximation for the diameter of the moon accurate to the nearest hundred miles.
Physics
2 answers:
slega [8]3 years ago
8 0

The approximation for the diameter of the moon accurate to the nearest hundred miles is s =  +- 2100 miles

<h3>Further explanation </h3>

Arc Measure definition is,  in a circle, arc degree measure is equal to the measure of the central angle that intercepts the arc. Whereas the arc Length definition is, In a circle, the length of an arc is a portion of the circumference. Where the letter "s" is used to represent arc length.      

s = r * \theta (Radian Measure and Arc of a Circle).

There is a formula which relates the arc length of a circle of radius, r, to the central angle, θ in radians.

The radian measure θ of a central angle is defined as the ratio of the length of the arc  the angle subtends s, divided by the radius of the circle r.

where s = the arc length

\theta = angle  in radians

0.5 degrees *  \frac{\pi}{180}  = 0.008726646 radians \\ r = 240000 miles  \\ s  = 240000 * 0.008726646 \\

s = 2094.4 miles or

s =  +- 2100 miles

So the approximation for the diameter of the moon accurate to the nearest hundred miles is s =  +- 2100 miles

<h3>Learn more</h3>
  1. Learn more about the radian measure of the angle brainly.com/question/4675968

<h3>Answer details</h3>

Grade:  9

Subject:  physics

Chapter:  the radian measure of the angle

Keywords:  moon

laiz [17]3 years ago
3 0
The subtended angle and by an arc is given by:
S = r∅
Although the arc is circular, the huge amount of distance means that it is almost equivalent to the director.
D = 240,000 x (0.5 x π)/180
D = 2094 miles
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3 years ago
A steel ball rolls with a constant velocity on a tabletop 0.950 m high it rolls off and hit the ground 0.352 m from the edge of
sp2606 [1]

Answer:

0.799 m/s if air resistance is negligible.

Explanation:

For how long is the ball in the air?

Acceleration is constant. The change in the ball's height \Delta h depends on the square of the time:

\displaystyle \Delta h = \frac{1}{2} \;g\cdot t^{2} + v_0\cdot t,

where

  • \Delta h is the change in the ball's height.
  • g is the acceleration due to gravity.
  • t is the time for which the ball is in the air.
  • v_0 is the initial vertical velocity of the ball.
  • The height of the ball decreases, so this value should be the opposite of the height of the table relative to the ground. \Delta h = -0.950\;\text{m}.
  • Gravity pulls objects toward the earth, so g is also negative. g \approx -9.81\;\text{m}\cdot\text{s}^{-2} near the surface of the earth.
  • Assume that the table is flat. The vertical velocity of the ball will be zero until it falls off the edge. As a result, v_0 = 0.

Solve for t.

\displaystyle \Delta h = \frac{1}{2} \;g\cdot t^{2} + v_0\cdot t;

\displaystyle -0.950 = \frac{1}{2} \times (-9.81) \cdot t^{2};

\displaystyle t^{2} =\frac{-0.950}{1/2 \times (-9.81)};

t \approx 0.440315\;\text{s}.

What's the initial horizontal velocity of the ball?

  • Horizontal displacement of the ball: \Delta x = 0.352\;\text{m};
  • Time taken: \Delta t = 0.440315\;\text{s}

Assume that air resistance is negligible. Only gravity is acting on the ball when it falls from the tabletop. The horizontal velocity of the ball will not change while the ball is in the air. In other words, the ball will move away from the table at the same speed at which it rolls towards the edge.

\begin{aligned}\text{Rolling Velocity}&=\text{Horizontal Velocity} \\&= \text{Average Horizontal Velocity}\\ &=\frac{\Delta x}{\Delta t}=\frac{0.352\;\text{m}}{0.440315\;\text{s}}=0.0799\;\text{m}\cdot\text{s}^{-1}\end{aligned}.

Both values from the question come with 3 significant figures. Keep more significant figures than that during the calculation and round the final result to the same number of significant figures.

3 0
3 years ago
One wire carries a current of I1= 2 Amps, and the other carries a parallel current (same direction, wires are side by side) of I
Yuki888 [10]

Answer:F=3\times 10^{-5} N

Explanation:

Given

I_1=2 Amps

I_2=0.75 Amps

Length of each wires\left ( L\right )=5 m

Distance between wires \left ( r\right )=5 cm

Force per unit length =\frac{\mu_0I_1I_2}{2\pi r}

F'=\frac{2\times 10^{-7}\times 2\times 0.75}{2\pi \times 0.05}

F'=6\times 10^{-6}

Force for L=5 m

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6 0
3 years ago
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According to Newton laws of motion, 
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Here, m = 1,560 Kg
a = 1.30 m/s²

Substitute their values, 
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In short, Your Answer would be Option C

Hope this helps!
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bogdanovich [222]

Force

Explanation:

so force is your answer see why b/c

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