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Eddi Din [679]
3 years ago
9

If one redskin and 4 golden roughs cost $1.65, whereas 2 redskins and 3 golden roughs cost $1.55, how much does each type or swe

et cost?
Mathematics
1 answer:
Bas_tet [7]3 years ago
5 0

Answer:

Redskins cost $0.25 and golden roughs cost $0.35.

Step-by-step explanation:

Let r be the cost of a redskin and g the cost of golden roughs. So we have the system of equations:

r + 4g = 1.65

2r + 3g = 1.55

Multiply the first equation by -2:

-2r - 8g = -3.30

Adding this to the second equation:

-5g = -1.75

g = 0.35.

Now substitute this into the first equation:

r + 4*0.35 = 1.65

r  = 1.65 - 1.40

r = 0.25.

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Answer:

M=8 Y=-2

Step-by-step explanation:

this is the slope and b

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3 years ago
Marc buys three magazines for $7.50 at a school fundraiser. If all magizines in the fundraiser cost the same, what is the consta
mafiozo [28]

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3 years ago
What is 17. 60 divided by 8 in short division?
lesantik [10]
The answer's 2.2
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8 0
3 years ago
Find the lengths and slopes of the diagonals to name the parallelogram. Choose the most specific name. E (-2, -4), F(0, -1), G(-
Kay [80]

Answer:

1) d) Square

2) Proofs that PWRS is a rhombus are

Length of QS ≠ PR and

Slope of segment QR and PS is -1/2 and Slope of segment RS and QP is -2.

Step-by-step explanation:

The given points (x, y) of the parallelogram are;

E(-2, -4), F(0, -1), G(-3, 1), H(-5, -2)

The slope, m, of the segments are found as follows;

Slope, \, m =\dfrac{y_{2}-y_{1}}{x_{2}-x_{1}}

By computation, the slope of segment EF = 1.5

The slope of segment FG = -0.67

The slope of segment GH = 1.5

The slope of segment HE = -0.67

Therefore, EF is parallel to GH and FG is parallel to HE

The length of the sides are;

\sqrt{\left (y_{2}-y_{1}  \right )^{2}+\left (x_{2}-x_{1}  \right )^{2}}

By computation, the length of segment EF = 3.61

The length of segment FG = 3.61

The length of segment GH = 3.61

The length of segment HE = 3.61

The diagonals are;

EG and FH

The length of segment EG = 5.099

The length of segment FH = 5.099

Therefore, the diagonals are equal and the parallelogram is a square

2) The given dimensions are;

P(-1, 3), Q(-2, 5), R(0, 4), S(1, 2)

A rhombus has all sides equal

The length of segment PQ = 2.24

The length of segment QR = 2.24

The length of segment RS = 2.24

The length of segment PS = 2.24

The diagonals are;

QS and PR

The length of segment QS = 4.24

The length of segment PR = 1.41

The slope of segment QR = -0.5

The slope of segment PS = -0.5

The slope of segment RS = -2

The slope of segment QP = -2

Therefore, QS≠QR the parallelogram is a rhombus

The correct option ;

Length of QS ≠ PR and

Slope of segment QR and PS is -1/2 and Slope of segment RS and QP is -2.

Where there are acute angles in parallelogram PQRS, then the correct option is d) Length of QR and PS is 2.2 and Length of RS and QP is 2.2

8 0
3 years ago
What is the decimal 6.9 as a fraction
Verizon [17]

6.9 = 6.9 / 1

Numerator  = 6.9 × 10 = 69
Denominator  = 1 × 10 = 10

Numerator / Denominator = 69 / 10

Simplifying our fraction

= 69/10

= 69/10

= 6  9/10
5 0
3 years ago
Read 2 more answers
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