n, n + 2, n + 4 - three consecutive even integers
the twice the sum of the second and third: 2[(n + 2) + (n + 4)]
twelve less than six times the first: 6n - 12
The equation:
2[(n + 2) + (n + 4)] = 6n - 12
2(n + 2 + n + 4) = 6n - 12
2(2n + 6) = 6n - 12 <em>use distributive property</em>
(2)(2n) + (2)(6) = 6n - 12
4n + 12 = 6n - 12 <em>subtract 12 from both sides</em>
4n = 6n - 24 <em>subtract 6n from both sides</em>
-2n = -24 <em>divide both sides by (-2)</em>
n = 12
n + 2 = 12 + 2 = 14
n + 4 = 12 + 4 = 16
<h3>Answer: 12, 14, 16</h3>
There is no graph please provide a graph or equation
P(x) = 4x + 1550 <== ur function
selling only 50 copies...
P(50) = 4(50) + 1550
P(50) = 200 + 1550
P(50) = 1750....so the printing cost for 50 copies is 1750
1750 = 50x....x = cost of each book
1750/50 = x
35 = x.......u would have to sell each book for $ 35 <===
Answer:
49π / 4
Step-by-step explanation:
πr²
pi x radius²
radius = d ÷ 2 = 3.5
49π / 4
☺️
The required matrix is:
![\left[\begin{array}{ccc}-25&17&0\\8&-1&3\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-25%2617%260%5C%5C8%26-1%263%5C%5C%5Cend%7Barray%7D%5Cright%5D)
Step-by-step explanation:
We need to apply elementary row operation -2R₂+3R₁ tothe matrix:
![A=\left[\begin{array}{ccc}-3&5&2\\8&-1&3\\\end{array}\right]](https://tex.z-dn.net/?f=A%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-3%265%262%5C%5C8%26-1%263%5C%5C%5Cend%7Barray%7D%5Cright%5D)
Multiplying Row 2 with -2 and Row1 with 3 and adding,
-9 15 6
-16 2 -6
----------
-25 17 0
After applying this operation, Row 1 will be changed while Row 2 will remain same because we get -2R₂+3R₁ -> R₁
The required matrix is:
![\left[\begin{array}{ccc}-25&17&0\\8&-1&3\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-25%2617%260%5C%5C8%26-1%263%5C%5C%5Cend%7Barray%7D%5Cright%5D)
Keywords: Matrices, elementary row operation
Learn more about matrices at:
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