The answer is 2) 4.7 g/mL because the solid use 17 mL and 80g/17mL is 4,7 g/mL.
Use the equation d = m/v or density equals mass over volume. 420/50.4=8.3333 or 8 and one third.
<span>0.430 ml is the number of moles/molecules in 9.63 | of h2s gas. It has been proven by Einstein and many other chemists that .430 ml is the viable solution. One has to take to mind the density of the object when calculating this problem.</span>
3.25= 0.02830 moles
hope its right :(
Answer:
We know that : MgSO4.7H2O + heat = MgSO4 + 7 H2O Also, molar mass of MgSO4*7H2O = 246.47 g/mole molar mass of MgSO4(anhydrous) = 120.415 g/mole Therefore, Remaining mass of anhydrous magnesium sulfate = (20 grams of MgSO4⋅7H2O) / (246.4746 grams of MgSO4⋅7H2O/mole) x (1 mole of MgSO4 / 1 mole of MgSO4⋅7H2O) x (120.3676 grams of MgSO4/mole ) = 7.7 grams of MgSO4
