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VashaNatasha [74]
2 years ago
15

A factory made 886 jars of peanut butter. 443 of the jars contained creamy peanut butter. What percentage of the jars of peanut

butter was creamy?
Mathematics
1 answer:
Rzqust [24]2 years ago
7 0

Answer:

50%

Step-by-step explanation:

To find the percentage, we need to divide the amount of creamy peanut butter by the total amount of peanut butter. In this case, there are 443 jars with creamy peanut butter and 886 total jars.

What is 443/886? Well, you could divide it out, but you could also notice that 443 is exactly half of 886 and simplify to 1/2, which is equal to 0.5. Either way works, but one's just a lot quicker.

Next, we have to convert the decimal - 0.5 - into a percentage. To do this, we move the decimal point to the right two spots, getting us to 50, and then slap a percentage sign on there giving us a final answer of 50%.

Hopefully that's helpful! :)

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In 1999, there were 9860 Great Danes registered with the American Kennel Club. The number of registered Labrador Retrievers was
jekas [21]

Answer:

153,997 Labrador Retrievers

Step-by-step explanation:

Let's make an equation for this problem. We know that there were 9,860 Great Danes. The number of Labrador Retrievers was 6,997 more than 15 times the number of registered Great Danes. More than can be changed to a plus sign. 15 times the number of Great Danes is 15 times 9,860. The equation is now 15*9,860 + 6,997.

15*9,860 is 147,900

147,900 + 6,997 is 153,997.

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3 years ago
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WHAT IS X IF THE EQUATION IS X - 3 = 6?
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Answer:

9

Step-by-step explanation:

You substitute 9 for x and 9 - 3 = 6


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3 years ago
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If Darren completed 25% of his science project on Monday, what percentage of his project is left to complete? A) 25% B) 50% C) 7
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3 years ago
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PICTURE IS SHOWN Help
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A survey of 25 grocery stores revealed that the mean price of a gallon of milk was $2.98, with a standard error of $0.10. What i
Gnesinka [82]

Answer:

95% confidence interval: (2.784,3.176)

Step-by-step explanation:

We are given the following information in the question:

Sample size, n = 25

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Standard error = $0.10

Alpha = 0.05

95% confidence interval:

\mu \pm z_{critical}(\text{Standard error})

Putting the values, we get,

z_{critical}\text{ at}~\alpha_{0.05} = 1.96

2.98 \pm 1.96(0.10) = 2.98 \pm 0.196 = (2.784,3.176)

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