Energy required=mass*specific heat*temperature change
=10*4.184*57.2
=2393.248j
=2.39*10^3
Answer:
uh i think its D All of the above
Explanation:
sorry if its wrong
The new pressure would be = 4.46 atm
<h3>Further explanation</h3>
Given
V₁=6.7 L(at STP, 1 atm 273 K)
V₂=1.5 L
Required
The new pressure
Solution
Boyle's Law
At a constant temperature, the gas volume is inversely proportional to the pressure applied
![\rm p_1V_1=p_2.V_2\\\\\dfrac{p_1}{p_2}=\dfrac{V_2}{V_1}](https://tex.z-dn.net/?f=%5Crm%20p_1V_1%3Dp_2.V_2%5C%5C%5C%5C%5Cdfrac%7Bp_1%7D%7Bp_2%7D%3D%5Cdfrac%7BV_2%7D%7BV_1%7D)
P₂ = (P₁V₁)/V₂
P₂ = (1 atm x 6.7 L)/1.5 L
P₂ = 4.46 atm
Answer: Total pressure inside of a vessel is 0.908 atm
Explanation:
According to Dalton's law, the total pressure is the sum of individual partial pressures. exerted by each gas alone.
![p_{total}=p_1+p_2+p_3](https://tex.z-dn.net/?f=p_%7Btotal%7D%3Dp_1%2Bp_2%2Bp_3)
= partial pressure of nitrogen = 0.256 atm
= partial pressure of helium = 203 mm Hg = 0.267 atm (760mmHg=1atm)
= partial pressure of hydrogen =39.0 kPa = 0.385 atm (1kPa=0.00987 atm)
Thus ![p_{total}=p_{H_2}+p_{He}+p_{H_2}](https://tex.z-dn.net/?f=p_%7Btotal%7D%3Dp_%7BH_2%7D%2Bp_%7BHe%7D%2Bp_%7BH_2%7D)
=0.256atm+0.267atm+0.385atm =0.908atm
Thus total pressure (in atm) inside of a vessel is 0.908
Answer:
Group 16 Melting point 220.8°C, 429.4°F, 494 K
Period 4 Boiling point 685°C, 1265°F, 958 K
Explanation: