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3 years ago

Describe the spin of carbon-14's valence electrons and explain how you came about your answer.

Chemistry

1 answer:

Snezhnost [94]3 years ago

8 0

we have to know the spin of valence electrons of carbon-14

There are four unpaired electron which are called as valence electron also.The spin of the four unpaired electron is either upfilled or down filled.

The ground state electronic configuration of C-atom is 1s²2s²2p² and one electron from 2s orbital gets excited to 2p orbital. The elctronic configuration in excited state is 1s²2s¹ $2p_{x}^{1} 2p_{y}^{1}2p_{z}^{1}$ .

The electron jumps because half-filled orbitals are more stable. Exchange energy is less than pairing energy.

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3 years ago

The heat of fusion for a substance is 122 joules per gram. How many joules of heat are need to melt 7.50 grams of this substance

daser333 [38]

<h3>Answer:</h3>

915 Joules

<h3>Explanation:</h3>

The heat of fusion is the heat that is required to convert a given mass of a substance from solid state to liquid state without change in temperature.
In this case, we are given specific heat of a substance as 122 joules per gram
It means that amount of heat equivalent to 122 joules is required to change 1 gram of the substance from solid state to liquid state.

Therefore, we can determine the amount of heat needed to change 7.5 grams of the substance from solid to liquid state.

1 g = 122 Joules

7.5 g = ?

= 122 × 7.5

= 915 Joules

Thus, 7.5 g of the substance at its melting point will require 915 Joules of heat to melt.

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3 years ago

Why is ice in a glacer considered to be a mineral but water a glacier is not

-Dominant- [34]

If you have a book, read it!! I promise you, it tells you this answer!

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2 years ago

A piece of unknown metal with mass 30 g is heated to 110.0 °C and dropped into 100.0 g of water at 20.0 °C. The final temperatur

Ymorist [56]

<u>Answer:</u> The specific heat of metal is 0.821 J/g°C

<u>Explanation:</u>

When metal is dipped in water, the amount of heat released by metal will be equal to the amount of heat absorbed by water.

$Heat_{\text{absorbed}}=Heat_{\text{released}}$

The equation used to calculate heat released or absorbed follows:

$Q=m\times c\times \Delta T=m\times c\times (T_{final}-T_{initial})$

$m_1\times c_1\times (T_{final}-T_1)=-[m_2\times c_2\times (T_{final}-T_2)]$ ......(1)

where,

q = heat absorbed or released

$m_1$ = mass of metal = 30 g

$m_2$ = mass of water = 100 g

$T_{final}$ = final temperature = 25°C

$T_1$ = initial temperature of metal = 110°C

$T_2$ = initial temperature of water = 20.0°C

$c_1$ = specific heat of metal = ?

$c_2$ = specific heat of water = 4.186 J/g°C

Putting values in equation 1, we get:

$30\times c_1\times (25-110)=-[100\times 4.186\times (25-20)]$

$c_1=0.821J/g^oC$

Hence, the specific heat of metal is 0.821 J/g°C

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3 years ago

Plant cells have large central ________________ . These are also found in animal cells but are much smaller Question 3 options:

Phantasy [73]

Answer:

vacuoles

Explanation:

Vacuoles are not only found in animal and plant cells, but on every given diagram vacuoles are huge and singular on a plant cell. Animals however, there are multiple and are much smaller

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