Ideal gas law:
PV=nRT ⇒ V=nRT / P
P=pressure=1 atm
V=volume
n=number moles=2.10 moles
R=0,082 Atm l/ºK mol
T=temperature=273 K
V=(2.10 moles*0.082 (atm l)/º(K mol)*237ºK) / 1 atm=47.01 litres
47.1 L
Answer:
Judging from the wording of he question, you mean units. If that is indeed the case, the answer is g/Mol (grams per mol)
Let me know if my interpretation is incorrect and please tell me what you are actually trying to find.
