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2 years ago

Identify the fundamental particles that make up a proton.

1 answer:

4 0

The three main quarks that make up a
proton are two up quarks and one down
quarks which is the main reason protons
are positive aswell.

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PLEASEEEE HELP :( it would mean a lot

Elis [28]

Answer:

Each object exerts a force on the other, and the two forces are equal and in opposite directions

Explanation:

Newton's 3rd Law Of Motion:

For every action, there is an equal and opposite reaction.

5 0

3 years ago

Read 2 more answers

Two long, parallel wires are separated by 2.2 mm. Each wire has a 32-AA current, but the currents are in opposite directions. Pa

Alex

Answer:

$B=1.1636*10^{-3}T$

Explanation:

Given data

$d_{wires}=2.2mm=0.022m\\ I_{current}=32A\\$

To find

Magnitude of the net magnetic field B

Solution

The magnitude of the net magnetic field can be find as:

$B=2*u\frac{I}{2\pi r}\\ B=2*(4\pi*10^{-7} )\frac{32}{2\pi (0.022/2)} \\ B=1.1636*10^{-3}T$

3 0

3 years ago

Which three quantities can be used to calculate acceleration?

PtichkaEL [24]

D is the correct answer, assuming that this is the special case of classical kinematics at constant acceleration. You can use the equation V = Vo + at, where Vo is the initial velocity, V is the final velocity, and t is the time elapsed. In D, all three of these values are given, so you simply solve for a, the acceleration.
A and C are clearly incorrect, as mass and force (in terms of projectile motion) have no effect on an object's motion. B is incorrect because it is not useful to know the position or distance traveled, unless it will help you find displacement. Even then, you would not have enough information to use a kinematics equation to find a.

4 0

4 years ago

Can science answer every question

Alla [95]

No because your opinion and beliefs answers many questions

5 0

3 years ago

Read 2 more answers

calculate earths velocity of approach toward the sun when earth in its orbit is at an extremum of the latus rectum through the s

IceJOKER [234]

Answer:

Hello your question is incomplete below is the complete question

Calculate Earths velocity of approach toward the sun when earth in its orbit is at an extremum of the latus rectum through the sun, Take the eccentricity of Earth's orbit to be 1/60 and its Semimajor axis to be 93,000,000

answer : V = 1.624* 10^-5 m/s

Explanation:

First we have to calculate the value of a

a = 93 * 10^6 mile/m * 1609.344 m

= 149.668 * 10^8 m

next we will express the distance between the earth and the sun

$r = \frac{a(1-E^2)}{1+Ecos\beta }$ --------- (1)

a = 149.668 * 10^8

E (eccentricity ) = ( 1/60 )^2

$\beta$ = 90°

input the given values into equation 1 above

r = 149.626 * 10^9 m

next calculate the Earths velocity of approach towards the sun using this equation

$v^2 = \frac{4\pi^2 }{r_{c} }$ ------ (2)

Note :

Rc = 149.626 * 10^9 m

equation 2 becomes

( $V^2 = (\frac{4\pi^{2} }{149.626*10^9})$

therefore : V = 1.624* 10^-5 m/s

4 0

4 years ago