Ek = (m*V^2) / 2 where m is mass and V is speed, then we can take this equation and manipulate it a little to isolate the speed.
Ek = mv^2 / 2 — multiply both sides by 2
2Ek = mv^2 — divide both sides by m
2Ek / m = V^2 — switch sides
V^2 = 2Ek / m — plug in values
V^2 = 2*30J / 34kg
V^2 = 60J/34kg
V^2 = 1.76 m/s — sqrt of both sides
V = sqrt(1.76)
V = 1.32m/s (roughly)
Answer:
3 meters per second
Explanation:
72 divided by 3= 24 meters in 8 seconds
24/8= 3, so 3 meters per second
Answer:

Explanation:
Given that,
The magnitude of vector A, 
The magnitude of vector B, 
Scalar product of A and B, 
The formula for the scalar product is given by :

Where,
is the angle between A and B.

The formula for the vector product is given by :

So, the vector product between these two vectors is
.
I think B......................
We can’t exactly measure how fast speed is traveling .