Hi can someone help me p.lea.se i need help i will give brainliestwith steps
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The equation is
This case asking the end result in the form of a slope-intercept.
<u>Step-1: find out the gradient. </u>
10x + 2y = -2
We isolate the y variable on the left side. Subtract both sides by 10x, we get:
2y = - 10x - 2
Divide both sides by two
y = -5x -1
The slope-intercept form is , with the coefficient m as a gradient. Therefore, the gradient is m = -5.
If you want a shortcut to find a gradient from the standard form, implement this:
10x + 2y = −2 ⇒ a = 10, b = 2
<u>Step-2:</u> the conditions of the two parallel lines
The gradient of parallel lines is the same . So
<u>Final step:</u> figure out the equation, in slope-intercept form, of the parallel line to the given line and passes through the point (0, 12)
We use the point-slope form.
Given that
- m = -5
- (x₁, y₁) = (0, 12)
y - 12 = - 5(x - 0)
y - 12 = - 5x
After adding both sides by 12, the results is
<u>Alternative steps </u>
Substitutes m = -5 and (0, 12) to slope-intercept form
12 = -5(0) + c
Constant c is 12 then arrange the slope-intercept form.
Similar results as above, i.e.
<u>Note: </u>
- A similar problem brainly.com/question/10704388
- Investigate the relationship between two lines brainly.com/question/3238013
- Write the line equation from the graph brainly.com/question/2564656
Keywords: given line, the equation, slope-intercept form, standard form, point-slope, gradien, parallel, perpendicular, passes, through the point, constant
Start by looking at the vertex form of a quadratic function, f(x) = a(x - h)^2 + k. The variables h and k are the values of the vertex. Plug those in to get f(x) = a(x - 4)^2 + 5. To find the variable a, plug in the point given for the x and y values. So, you get (21) = a((8) - 4)^2 + 5. Solve for a algebraically, and you get a = 1. Finally, plug everything in and simplify the equation. You should get that the quadratic function is f(x) = x^2 - 8x + 21. Hope this helps!
