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3 years ago

What is the alcohol in this?

Chemistry

1 answer:

disa [49]3 years ago

6 0

I reckon it looks like a 40% two six

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(tco 2) an atom has 6 protons, 8 neutrons, and 6 electrons. its atomic mass is

kirza4 [7]

Answer: 14 Explanation: Mass number: the total number of protons and neutrons in a nucleus.

Mass number = Protons + Neutrons = 6 + 8 = 14

8 0

3 years ago

Consider the following reaction NHAHS(s)NH3(g) + H2S(g) If a flask maintained at 302 K contains 0.196 moles of NH4HS(s) in equil

quester [9]

Answer:

Kc = 3.72 × 10⁶

Explanation:

Let's consider the following reaction:

NH₄HS(g) ⇄ NH₃(g) + H₂S(g)

At equilibrium, we have the following concentrations:

[NH₄HS] = 0.196 M (assuming a 1 L flask)

[NH₃] = 9.56 × 10² M

[H₂S] = 7.62 × 10² M

We can replace this data in the Kc expression.

$Kc=\frac{[NH_{3}] \times [H_{2}S] }{[NH_{4}HS]} =\frac{9.56 \times 10^{2} \times 7.62 \times 10^{2}}{0.196} =3.72 \times 10^{6}$

7 0

2 years ago

#1: Jim, Jane, Ann, and Bill measure an object’s length, density, mass, and volume, respectively. Which student’s measurement mi

STatiana [176]

1. The <span>student with a measurement that might be in centimeters is A. Bill.
2. C</span><span>entimeters in 0.05 kilometers is </span>C. 5,000
solution:
0.05 km x (1000 meters/ 1 km)
= 50 meters x (100 cm/ 1 meter)
=5000 cm

7 0

2 years ago

Read 2 more answers

In a classical long run supply model the economy is always doing what

ch4aika [34]

Answer:

Economy is always at the full employment level of output

Explanation:

The economy in a classical long-run supply model will always have the same economic output

8 0

2 years ago

Si desea preparar 300 gramos de una solución de azúcar en agua que tenga una concentración de 20% m/m en cuanto gramos de soluto

Digiron [165]

Answer:

$m_{soluto}=60g$

Explanation:

¡Hola!

En este caso, al considerar la unidad de concentración de porcentaje masa/masa, podemos escribir su fórmula como:

$\%m/m=\frac{m_{soluto}}{m_{solucion}}*100\%$

Podemos identificar la masa de soluto (azúcar) como la incógnita, y resolverla como se muestra a continuación:

$m_{soluto}=\frac{\%m/m*m_{solucion}}{100\%}\\\\m_{soluto}=\frac{20\%*300g}{100\%}\\\\m_{soluto}=60g$

¡Saludos!

5 0

3 years ago