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stellarik [79]
3 years ago
12

if you placed the contents of a packet of powdered iced tea mix into a bottle of water and shook it, which of the following woul

d be true? A. The iced tea mix would dissolve the water. B. The iced tea mix would be the solvent. C. The water would be the solvent. D. The solution would be homogenous if half of the powdered solute sat at the bottom of the bottle.
Chemistry
2 answers:
victus00 [196]3 years ago
3 0
If you placed the contents of a packet of powdered iced tea mix into a bottle of water and shook it, D. The solution would be homogenous if half of the powdered solute sat at the bottom of the bottle.
Sonbull [250]3 years ago
3 0

Answer: Option (C) is the correct answer.

Explanation:

A homogeneous solution is defined as the solution in which solute particles are evenly distributed in a solvent.

A homogeneous solution is a clear solution.

For example, salt dissolved in water is a homogeneous mixture.

On the other hand, a solution in which solute particles are unevenly distributed in a solvent then it is known as a heterogeneous solution.

In a solution, a substance present in small quantity is known as solute and a substance present in large quantity is known as a solvent.

Therefore, when powdered iced tea mix is added into a bottle of water then powdered iced tea is the solute and water is the solvent.

Thus, we can conclude that the statement, water would be the solvent is true.

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The answers that fit the blanks are SMALL and LITTLE, respectively. The particles or molecules or fas are small which makes it loose and easily moves around, and these only exert little attraction for other gas particles. The answer for this would be option D.
5 0
3 years ago
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When 8.00x10^22 molecules of ammonia react with 7.00x10^22 molecules of oxygen according to the chemical equation shown below, h
Pavel [41]
NH₃:

N = 8*10²²
NA = 6.02*10²³

n = N/NA = 8*10²²/6.02*10²³ ≈ 1.33*10⁻¹=0.133mol

O₂:

N=7*10²²
NA = 6.02*10²³

n = N/NA = 7*10²²/6.02*10²³ = 1.16*10⁻¹=0.116mol

4NH₃                   <span>+                        3O</span>₂                      ⇒<span>          2N</span>₂<span> + 6H</span>₂<span>O
</span>4mol                     :                        3mol                   :             2mol
0.133mol             :                        0.116mol           :             0,0665mol
limiting reactant

N₂:

n = 0.0665mol
M = 28g/mol

m = n*M = 0.0665mol*28g/mol = <u>1,862g</u>
6 0
3 years ago
Draw the simplified curved arrow mechanism for the reaction of butan-2-one and CH3Li to give the major product.
Yuki888 [10]

Answer:

Follows are the solution to this question:

Explanation:

Please find the image file of the chemical reaction in the attachment:

In a water medium, the CH3- type CH 3Li is a heavy nucleophile that attacks the carbonyl carbon atom to form the alkoxide ion, which will then be protonated to form alcohol.

8 0
3 years ago
Activity In this activity, you’ll draw and count atoms to understand how nitrogen and hydrogen react to make ammonia. Begin by s
vredina [299]

Answer:

Explanation:

3 0
3 years ago
Problem Page Question It takes to break a carbon-carbon single bond. Calculate the maximum wavelength of light for which a carbo
Marizza181 [45]

This is a incomplete question. The complete question is:

It takes 348 kJ/mol to break a carbon-carbon single bond. Calculate the maximum wavelength of light for which a carbon-carbon single bond could be broken by absorbing a single photon. Round your answer to correct number of significant digits

Answer: 344 nm

Explanation:

E=\frac{Nhc}{\lambda}

E= energy  = 348kJ= 348000 J  (1kJ=1000J)

N = avogadro's number = 6.023\times 10^{23}

h = Planck's constant = 6.626\times 10^{-34}Js&#10;

c = speed of light = 3\times 10^8ms^{-1}

348000=\frac{6.023\times 10^{23}\times 6.626\times 10^{-34}\times 3\times 10^8}{\lambda}

\lambda=\frac{6.023\times 10^{23}\times 6.626\times 10^{-34}\times 3\times 10^8}{348000}

\lambda=3.44\times 10^{-7}m=344nm    1nm=10^{-9}m

Thus the maximum wavelength of light for which a carbon-carbon single bond could be broken by absorbing a single photon is 344 nm

5 0
3 years ago
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