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LenKa [72]
3 years ago
9

Under conditions of conservation of energy where the initial energy object is only gravitiational potential energy and the final

energy is only kinetic, write an equation to calculate the final velocity of the object. Ignore all friction. Show all work
Physics
1 answer:
Otrada [13]3 years ago
3 0

Answer:

The equation to calculate the final velocity of the object.---

Final velocity (v) of an object equals initial velocity (u) of that object plus acceleration (a) of the object times the elapsed time (t) from u to v. Use standard gravity, a = 9.80665 m/s2, for equations involving the Earth's gravitational force as the acceleration rate of an object.

Explanation:

Also just so you know this isn't my answer I got it from here brainly.com/question/20016151 from  im2slowwwww

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There are 4 hydrogens on the right side (2\mathrm H_2=4\mathrm H), and 2 hydrogens on the left per molecule of \mathrm H_2. To get the same number of hydrogens on both sides, the coefficient should be 2.

(Then the number of oxygens will be consistent, since 2\mathrm H_2\mathrm O contributes 2 oxygens, and so does \mathrm O_2.)

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Answer:

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Explanation:

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3 years ago
What force must the deltoid muscle provide to keep the arm in this position?
ruslelena [56]

Answer:

Deltoid Force, F_{d} = \frac {r_{a}mgsin\alpha_{a}}{r_{d}sin\alpha_{d}}

Additional Information:

Some numerical information are missing from the question. However, I will derive the formula to calculate the force of the deltoid muscle. All you need to do is insert the necessary information and calculate.  

Explanation:

The deltoid muscle is the one keeping the hand arm in position. We have two torques that apply to the rotating of the arm.

1. The torque about the point in the shoulder for the deltoid muscle, T_{Deltoid}

2. The torque of the arm, T_{arm}  

Assuming the arm is just being stretched and there is no rotation going on,

                        T_{Deltoid} = 0

                       T_{arm} = 0

       ⇒           T_{Deltoid} = T_{arm}

                  r_{d}F_{d}sin\alpha_{d} = r_{a}F_{a}sin\alpha_{a}

Where,

r_{d} is radius of the deltoid

F_{d} is the force of the deltiod

\alpha_{d} is the angle of the deltiod

r_{a} is the radius of the arm

F_{a} is the force of the arm , F_{a} = mg  which is the mass of the arm and acceleration due to gravity

\alpha_{a} is the angle of the arm

The force of the deltoid muscle is,

                                 F_{d} = \frac {r_{a}F_{a}sin\alpha_{a}}{r_{d}sin\alpha_{d}}

but F_{a} = mg ,

                ∴            F_{d} = \frac {r_{a}mgsin\alpha_{a}}{r_{d}sin\alpha_{d}}

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