Students were asked to create roller coasters for marbles. The only requirement is that the roller coaster include at least one
1 answer:
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Answer:
Glaciologists use Glen–Nye Flow Law, to predict the movements of glaciers.
Explanation:
In some parts of the world, glaciers are an important natural resource. This is so because the nature and behaviour of glaciers are an impact the hydrologic, geologic, and ecological systems of their immediate location.
Due to the above, Glaciologists monitor and try to predict the movement and morphology of glaciers.
One of the techniques used by Glaciologists in the monitoring and prediction of glaciers in the use of markers.
The movement of markers is measured relative to the edges of the valley down which the glacier flows. The movement of the markers are then predicted using the Glen–Nye Flow Law.
The Glen–Nye Flow Law is expressed mathematically as follows:
∑=
∑= shear strain (flow) rate
<em>r </em>= stress
<em>n</em> = a constant between 2–4 (typically 3 for most glaciers) that increases with lower temperature
<em>k </em> = a constant dependent on temperature
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Answer:
(moving toward the incline.)
(moving away from the incline.)
(Assumption: .)
Explanation:
If , the potential energy of the block of
would be
when it was at the top of the incline.
If friction is negligible, all these energies would be converted to kinetic energy when this block reaches the bottom of the incline. There shouldn't be any energy loss along the horizontal surface, either. Therefore, the kinetic energy of this block right before the collision would also be approximately
.
Calculate the velocity of that based on its kinetic energy:
.
A collision is considered as an elastic collision if both momentum and kinetic energy are conserved.
Initial momentum of the two blocks:
.
.
Sum of the momentum of each block right before the collision: approximately .
Sum of the momentum of each block right after the collision: .
For momentum to conserve in this collision, and
should ensure that
.
Kinetic energy of the two blocks right before the collision: approximately and
. Sum of these two values: approximately
.
Sum of the energy of each block right after the collision:
.
Similarly, for kinetic energy to conserve in this collision, and
should ensure that
.
Combine to obtain two equations about and
(given that
whereas
.)
.
Solve for and
(ignore the root where
.)
.
The collision flipped the sign of the velocity of the block. In other words, this block is moving backwards towards the incline after the collision.