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pshichka [43]
3 years ago
13

A building made with a steel structure is 565 m high on a winter day when the temperature is 0◦F. How much taller is the buildin

g when the temperature is 103◦F? The linear expansion coefficient of steel is 1.1 × 10−5 ( ◦C)−1 . Answer in units of cm.
Physics
1 answer:
anyanavicka [17]3 years ago
3 0

To solve this problem we apply the thermodynamic equations of linear expansion in bodies.

Mathematically the change in the length of a body is subject to the mathematical expression

\Delta L = L_0 \alpha \Delta T

Where,

L_0 = Initial Length

\alpha = Thermal expansion coefficient

\Delta T = Change in temperature

Since we have values in different units we proceed to transform the temperature to degrees Celsius so

0\°F \Rightarrow (0-32)*\frac{5}{9} = -17.77\°C

103\°F \Rightarrow (103-32)*(\frac{5}{9})= 39.44\°C

The coefficient of thermal expansion given is

\alpha = 1.1*10^{-5}/\°C

The initial length would be,

L_0 = 565m

Replacing we have to,

\Delta L = L_0 \alpha \Delta T

\Delta L = (565)(1.1*10^{-5})(39.44-(-17.77))

\Delta L = (565)(1.1*10^{-5})(39.44-(-17.77))

\Delta L = 0.355m

This means that the building will be 35.5cm taller

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In this case, volume of the can remains constant. The relationship between pressure and temperature at constant volume is given by:

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Then
\frac{ P_{1} }{ T_{1} } = \frac{ P_{2} }{ T_{2} }

Where
P1 = 40 psi
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T1 = 60°F ≈ 289 K
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Substituting;
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Harrizon [31]

Answer:

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Explanation:

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here we know that

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Answer:

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