Percentage Weight-in-volume is defined as the <em><u>number of grams of a solute in a 100 ml (milliliters) solution.</u></em>
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<u>Percentage Weight-in-volume</u> can tell us about the <em>degree of concentration of a given solution.</em>
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The solute can be <em>crystalline or non-crystalline in nature.</em>
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The <u>number of grams of glucose</u> present in a <u>5% glucose solution</u> is 5 grams.
- This question is based on a Percentage Weight-in-volume. The formula states that:
a% of a glucose solution =<u> a grams of glucose in a 100 mL solution</u>
Hence, 5% glucose solution = 5 grams of glucose / 100 mL solution
Therefore, the <u>number of grams of glucose</u> present in a <u>5% glucose solution</u> is 5 grams.
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Answer:
OH^-
Explanation:
Any substance that is able to neutralize acidity in the stomach is generally known as an antacid. There are various kinds of antacids that are in common use. It should be noted that the stomach is usually slightly acidic.
Milk of magnesia is the substance magnesium hydroxide with chemical formula Mg(OH)2. A solution of milk of magnesia contains Mg^2+ and OH^-.
Hence the negative ion contained in milk of magnesia is the hydroxide ion OH^-.
Answer:
The combustion of 59.7 grams of methane releases 3320.81 kilojoules of energy
Explanation:
Given;
CH₄ + 2O₂ → CO₂ + 2H₂O, ΔH = -890 kJ/mol
From the combustion reaction above, it can be observed that;
1 mole of methane (CH₄) released 890 kilojoules of energy.
Now, we convert 59.7 grams of methane to moles
CH₄ = 12 + (1x4) = 16 g/mol
59.7 g of CH₄ 
1 mole of methane (CH₄) released 890 kilojoules of energy
3.73125 moles of methane (CH₄) will release ?
= 3.73125 moles x -890 kJ/mol
= -3320.81 kJ
Therefore, the combustion of 59.7 grams of methane releases 3320.81 kilojoules of energy
Hello,
I believe that your answer would be <span>B. water freezes
</span>Hope this helps
Answer:
Write this in a word and skeleton equation:
Solid silver chloride and an aqueous solution of nitric acid are produced when a solution of silver nitrate is reacted with a solution of hydrochloric acid.
Explanation: