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defon
2 years ago
12

Tomatoes that regularly sell for $0.55 per pound are on sale for 20% off the regular price. What is the sale price?

Mathematics
1 answer:
Otrada [13]2 years ago
7 0
0.55*(1-0.2)=0.44 so it is 0.44
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Brainliest for correct answer, asap please.
jeka57 [31]

Answer:

Not a function

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Step-by-step explanation:

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8 0
3 years ago
Alice, Ben and Carol shared a sum of money they received. Alice received 1/5 of the money. The rest of the money was divided bet
Levart [38]

Answer:

$3

Step-by-step explanation:

The money shared by Ben and Carol was split ...

... Ben : Carol = 1 : 3

The difference of these ratio numbers is 2, and the difference in amount received is $6. Thus, each ratio unit must stand for $6/2 = $3.

... Ben received 1×$3 = $3

_____

<em>The Rest of the Story</em>

Carol received 3×$3 = $9. Together, Ben and Carol received $3 + 9 = $12, which is 4/5 of the total amount. Then the 1/5 of the total amount that Alice received is

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8 0
3 years ago
A company that manufactures guitars has a fixed cost of $100,000. It costs $100 to produce each guitar and the selling price is
miv72 [106K]

a. Write the cost function:: C(x) = 100x + 100,000 where x is number of guitars

---------------------------------

b. Write the revenue function:: R(x) = 300x where x is number of guitars

-----------------------

c. Find the profit function.

Profit = Revenue - Cost

P(x) = R(x) - C(x)

P(x) = [ R(x) ] - [ C(x) ]

P(x) = [ 300x ] - [ 100x+100,000 ]

P(x) = 300x - 100x-100,000

P(x) = 200x - 100,000

The break even point is when the profit is 0 dollars. You don't lose any money. And you don't gain any money.

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x = 800 (# of guitars made and sold)

7 0
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dedylja [7]
The first option and the third one
8 0
3 years ago
Analyze the asymptotes of the function.
koban [17]

Answer:

vertical asymptote at x=-1

horizontal asymptote at y=0

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y=\frac{1}{x+1}

To find vertical asymptote we set the denominator =0 and solve for x

x+1=0 (subtract 1 from both sides)

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So, vertical asymptote at x=-1

To find horizontal asymptote we look at  the degree of both numerator and denominator

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When the degree of numerator is less than the degree of denominator

then horizontal asymptote at y=0

5 0
3 years ago
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