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NeX [460]
3 years ago
14

How important is the resonance structure shown here to the overall structure of carbon dioxide?

Chemistry
1 answer:
Tcecarenko [31]3 years ago
6 0

1. Resonance structures are a better description of a Lewis dot structure .

2. Best resonance structure is the one with the least formal charge.


<u>EXPLAINATION OF RASONANCE STRUCTURE OF CARBON DIOXIDE</u>

1.Carbon dioxide has three resonance structures .

2. The CO2 molecule has a total of 16 valence electrons ,

  1C = 4 electrons

  2O= 12 electrons

<u>three resonance structures for  CO2</u>

1. The atoms in all three resonance structures have full octets;

 structure 1 will be more stable because it has no separation of charge.

2. Structures 2 and 3 show charge separation caused by the presence of formal charges on both oxygen atoms.  

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Use your experimentally determined value of ksp and show,by calculations, that ag2cro4 should precipitate when 5ml of 0.004m agn
Doss [256]
When the value of Ksp = 3.83 x 10^-11 (should be given - missing in your Q)

So, according to the balanced equation of the reaction:

and by using ICE table:

              Ag2CrO4(s)  → 2Ag+ (Aq) + CrO4^2-(aq)

initial                                     0                   0

change                              +2X                 +X

Equ                                       2X                   X

∴ Ksp = [Ag+]^2[CrO42-]

so by substitution:

∴ 3.83 x 10^-11 = (2X)^2* X

3.83 x 10^-11 = 4 X^3

∴X = 2.1 x 10^-4 

∴[CrO42-] = X = 2.1 x 10^-4 M

[Ag+] = 2X = 2 * (2.1 x 10^-4) 

                  = 4.2 x 10^-4 M

when we comparing with the actual concentration of [Ag+] and [CrO42-]

when moles Ag+ = molarity * volume

                               = 0.004 m * 0.005L

                               = 2 x 10^-5 moles
[Ag+] = moles / total volume
     
          = 2 x 10^-5 / 0.01L

          = 0.002 M

moles CrO42- = molarity * volume

                         = 0.0024 m * 0.005 L

                         = 1.2 x 10^-5 mol

∴[CrO42-] = moles / total volume

                 = (1.2 x 10^-5)mol / 0.01 L 

                 = 0.0012 M

by comparing this values with the max concentration that is saturation in the solution 

and when the 2 values of ions concentration are >>> than the max values o the concentrations that are will be saturated.

∴ the excess will precipitate out       
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3 years ago
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Eduardwww [97]

Answer:

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2 years ago
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Answer:

The molarity of the sulfuric acid is 0.018 M

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With the density, we can calculate how many liters are 100 g of solution:

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Now, we know that we have 95 g sulfuric acid in 0.0541 l solution. In 1 l, we have then:

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1.756 g * 1 mol / 98.08 g = 0.018 mol

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