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3 years ago

How important is the resonance structure shown here to the overall structure of carbon dioxide?

Chemistry

1 answer:

Tcecarenko [31]3 years ago

6 0

1. Resonance structures are a better description of a Lewis dot structure .

2. Best resonance structure is the one with the least formal charge.

<u>EXPLAINATION OF RASONANCE STRUCTURE OF CARBON DIOXIDE</u>

1.Carbon dioxide has three resonance structures .

2. The CO2 molecule has a total of 16 valence electrons ,

1C = 4 electrons

2O= 12 electrons

<u>three resonance structures for CO2</u>

1. The atoms in all three resonance structures have full octets;

structure 1 will be more stable because it has no separation of charge.

2. Structures 2 and 3 show charge separation caused by the presence of formal charges on both oxygen atoms.

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How many liters of hydrogen gas will be produced at STP from the reaction of 7.179×10^23 atoms of magnesium with 54.219g of phos

Alexeev081 [22]

Answer: The volume of hydrogen gas produced will be, 12.4 L

Explanation : Given,

Mass of $H_3PO_4$ = 54.219 g

Number of atoms of $Mg$ = $7.179\times 10^{23}$

Molar mass of $H_3PO_4$ = 98 g/mol

First we have to calculate the moles of $H_3PO_4$ and $Mg$ .

$\text{Moles of }H_3PO_4=\frac{\text{Given mass }H_3PO_4}{\text{Molar mass }H_3PO_4}$

$\text{Moles of }H_3PO_4=\frac{54.219g}{98g/mol}=0.553mol$

and,

$\text{Moles of }Mg=\frac{7.179\times 10^{23}}{6.022\times 10^{23}}=1.19mol$

Now we have to calculate the limiting and excess reagent.

The balanced chemical equation is:

$3Mg+2H_3PO_4\rightarrow Mg(PO_4)_2+3H_2$

From the balanced reaction we conclude that

As, 3 mole of $Mg$ react with 2 mole of $H_3PO_4$

So, 0.553 moles of $Mg$ react with $\frac{2}{3}\times 0.553=0.369$ moles of $H_3PO_4$

From this we conclude that, $H_3PO_4$ is an excess reagent because the given moles are greater than the required moles and $Mg$ is a limiting reagent and it limits the formation of product.

Now we have to calculate the moles of $H_2$

From the reaction, we conclude that

As, 3 mole of $Mg$ react to give 3 mole of $H_2$

So, 0.553 mole of $Mg$ react to give 0.553 mole of $H_2$

Now we have to calculate the volume of $H_2$ gas at STP.

As we know that, 1 mole of substance occupies 22.4 L volume of gas.

As, 1 mole of hydrogen gas occupies 22.4 L volume of hydrogen gas

So, 0.553 mole of hydrogen gas occupies $0.553\times 22.4=12.4L$ volume of hydrogen gas

Therefore, the volume of hydrogen gas produced will be, 12.4 L

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3 years ago

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WITCHER [35]

The answer is B on edge

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How much heat is absorbed in the formation of 1.00mole of HI(g) from H2 and I2?

nordsb [41]

I don’t know ?

Explanation:

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3 years ago

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dybincka [34]

Answer:

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Explanation:

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Mekhanik [1.2K]

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3 years ago