Answer:
The heat is 115478.4 J.
Explanation:
Given that,
Mass of water = 0.400 kg
Power = 200 W
Suppose, we determine how much heat must be added to the water to raise its temperature from 20.0°C to 89.0°C?
We need to calculate the heat
Using formula of heat

Where, m = mass of water
c = specific heat
Put the value into the formula


Hence, The heat is 115478.4 J.
A. a<span> = 1.3 m/s^2</span><span>; </span>FN<span> = 63.1 N</span>
Answer:
600
Explanation:
GPE=mgh (mass*gravitational force*height)
m=10 kg
g=10
h=6m
10*10*6= 600 Joules