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mixer [17]
2 years ago
13

As crust forms at the mid-ocean ridge, it gets pushed away from the ridge as newer crust forms. What is true about crust that fo

rms at the mid-ocean ridge?
A: crust further away from the mid-ocean ridge is younger and crust closer is older


B: crust further away from the mid-ocean ridge is older and crust closer is newer


C: crust is not created at the mid-ocean ridge


D: crust further away from the mid-ocean ridge and crust closer are the same age
Physics
2 answers:
MrRa [10]2 years ago
4 0
The to the question is D
Nuetrik [128]2 years ago
3 0

Answer:

Answer is A

Explanation:

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Tarzan, whose mass is 75 kg, is running from a cheetah. Tarzan is moving at 5 m/s when he grabs onto a hanging vine. How high of
Fiesta28 [93]

Answer:

Explanation:

His Kinetic energy = 1/2 m v^2

v = 5 m/s

m = 75 kg

Ke = 1/2 75 * 5^2

Ke = 937.5 Joules

This will be converted to PE when he reaches the maximum height he reaches. In other words KE = PE

PE = m * g * h

m = 75

g = 9.81

h = ?

PE = 937.5

937.5 = 75 * 9.81 * h

937.5 = 735.75 * h

937.5/735.75 = h

h= 1.27 meters

6 0
3 years ago
In which of these states is the age of consent 18 years old?
Andreas93 [3]

Answer:

all the ones that say

Explanation:

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2 years ago
When devising a model, scientists can only use the information available during their lifetime. This means that the current mode
11111nata11111 [884]

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6 0
3 years ago
Read 2 more answers
I will give brainly
denis23 [38]
Answer

Around 400 B.C.E, the Greek philosopher Democritus introduced the idea of the atom as the basic building block matter. Democritus though that atoms are tiny, uncuttable, solid particles that are surrounded by empty space and constantly moving at random.

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8 0
3 years ago
A particle moves along the curve below. y = sqrt(1 + x^3) As it reaches the point (2, 3), the y-coordinate is increasing at a ra
blagie [28]

Answer:7 cm/s

Explanation:

Given

Particle move along curve

y=\sqrt{1+x^3}

As it reaches the (2,3) its y coordinate is increasing at 14 cm/s

Differentiating y w.r.t time

\frac{\mathrm{d} y}{\mathrm{d} t}=\frac{3x^2}{2\sqrt{1+x^3}}\times \frac{\mathrm{d} x}{\mathrm{d} t}

Now at (2,3)

\frac{\mathrm{d} y}{\mathrm{d} t}=\frac{3\cdot 2^2}{2\sqrt{1+2^3}}\times \frac{\mathrm{d} x}{\mathrm{d} t}

14=\frac{3\times 4}{2\times \sqrt{9}}\times \frac{\mathrm{d} x}{\mathrm{d} t}

\frac{\mathrm{d} x}{\mathrm{d} t}=7 cm/s

7 0
2 years ago
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