The reaction is:
(C₂H₃O₂)²⁻ + NH₄⁺ = (NH₄)(C₂H₃O₂).
and 
are the spectator ions.
<h3><u>Explanation:</u></h3>
The reactants in the reaction is sodium acetate and ammonium carbonate. They form the soluble molecule sodium carbonate and slightly soluble ammonium acetate. This is a double displacement reaction.
Spectator ions in the reaction are those ions which are present in the reaction but they actually don't take part in the reaction that's happening and they remain same before and after the reaction. In this reaction, the spectator ions are sodium and carbonate which remain in ionized form in the solution before and after the reaction.
The excess reactant when 4.35 g of hydrogen reacts with 30.75g of hydrogen iodide is hydrogen
<h3>calculation</h3>
write the equation for the reaction
H2(g) + I2 (g) → 2HI (g)
find the mole of each reactant
moles = mass/molar mass
moles of H2= 4.35 g/2 g/mol= 2.175 moles
moles o I2 = 30.75 g/ 254 g/mo=0.1211 moles
0.1211 moles of I2 reacted with 0.1211 moles of H2 but there are more moles of H2 there Hydrogen was in excess
Answer:
Mass = 15.13 g
Explanation:
Given data:
Number of atoms of hydrogen = 8.11×10²³
Mass of ammonia formed = ?
Solution:
Chemical equation:
3H₂ + N₂ → 2NH₃
Number of moles of hydrogen:
1 mole contain 6.022× 10²³ atoms
8.11×10²³ atoms × 1 mol / 6.022× 10²³ atoms
1.35 mol
Now we will compare the moles of hydrogen and ammonia:
H₂ : NH₃
3 : 2
1.35 : 2/3×1.35 = 0.89 mol
Mass of ammonia:
Mass = number of moles × molar mass
Mass = 0.89 mol × 17 g/mol
Mass = 15.13 g
