Explanation:
Gay-Lussac's law states that the pressure of a given mass of gas varies directly with the absolute temperature of the gas when the volume is kept constant. Mathematically, it can be written as: {\displaystyle {\frac {P}{T}}=k}. It is a special case of the ideal gas law.
Plants combine water and Carbon dioxide from the air to make glucose for themselves, and giving off oxygen in the process. So CO2 and H2O would be on ther reactant side (left) with O2 and C6H12O6 being on the product side (right).
How many oxygen molecules are in 22.4 liters of oxygen gas
at 273k and 101.3kpa
First solve the number of moles of the oxygen gas by using
the ideal gas equation:
PV = nRT
Where n is the number of moles
n = PV/RT
n = (101 300 Pa) (22.4 L) (1 m3/1000 L ) / ( 8.314 Pa m3 /
mol K) ( 273 K)
n = 1 mol O2
the number of molecules can be solve using avogrados number
6.022x10^23 molecule / mole
molecules of one mole O2 = 6.022x 10^23 molecules
Answer:
V = 27.1 cm³
Explanation:
To get the volume from the density we can plug our values into the formula for density, mass over volume, and then we use algebra to get V.
13.9 g/cm³ = 377 g / V
(13.9)(V) = 377
V = 27.1 cm³
