Answer:
Keq = 1.17 × 10²⁰
Explanation:
Let's consider the following redox reaction.
Cu²⁺(aq) + Ni(s) → Cu(s) + Ni²⁺(aq)
We can identify 2 half-reactions.
Cathode (reduction): Cu²⁺(aq) + 2 e⁻ → Cu(s) E°red = 0.337 V
Anode (oxidation): Ni(s) → Ni²⁺(aq) + 2 e⁻ E°red = -0.257 V
The standard cell potential (E°) is the difference between the standard reduction potential of the cathode and the standard reduction potential of the anode.
E° = E°red, cat - E°red, an = 0.337 V - (-0.257V) = 0.594 V
We can calculate the equilibrium constant (Keq) using the following expression.
where,
n are the moles of electrons transferred
Answer: 6.02 x 10^25
Explanation:
In order to find the number of molecules you simply multiply the number of moles by 6.022 x 10^23.
1 mole is always equal to 6.022 x 10^23 no matter what element.
100.0 x 6.022 x 10^23 = 6.02 x 10^25
The answer only has three significant figures because 100.0 only has three.
Answer:
Carbon 12 and 13 are carbon isotopes, meaning that they have additional neutrons:
Carbon 12 has exactly 6 protons and 6 neutrons ( hence the 12 )
Carbon 13 has 6 protons and 7 neutrons ( hence the 13 )
They differ in the number of neutrons in the nucleus.
Names:
carbon-13, C-13
carbon-12, C-12
Answer:
197mL of 0,506M HCl
Explanation:
The reaction of HCl + BaCO₃ is:
BaCO₃(s) + 2HCl → BaCl₂(aq) + CO₂ + H₂O.
The moles of BaCO₃ in 9,85 g are:
9,85 g of BaCO₃ × 
= <em>0,0499 moles of BaCO₃</em>
As 1 mol of BaCO₃ reacts with two moles of HCl, for a complete reaction of BaCO₃ to dissolve this compound in water you need:
0,0499 moles of BaCO₃ × 
=<em> 0,0998 moles of HCl</em>
If you have a 0,506M HCl, you need to add:
0,0998 moles of HCl× 
= 0,197 L ≡ 197mL
I hope it helps!
Electrons are released, causing a flow of electrical current,<span>when sunlight strikes a photovoltaic cell.</span>
