The distance covered is 1000 m
Explanation:
The rocket is moving by uniformly accelerated motion, so we can find the distance it covers by using the following suvat equation:
where
s is the distance covered
v is the final velocity
t is the time
a is the acceleration
For the rocket in this problem, we have:
v = 445 m/s is the final velocity
is the acceleration
t = 4.50 s is the time
Substituting, we find the distance covered:
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A string with linear density 0.500 g/m.
Tension 20.0 N.
The maximum speed
The energy contained in a section of string 3.00 m long as a function of .
We are given following data for string with linear density held under tension :
μ = 0.5
= 0.5 x 10⁻³
T = 20 N
If string is L = 3m long, total energy as a function of is given by:
E = 1/2 x μ x L x ω² x A²
= 1/2 x μ x L x
= 7.5 x 10⁻⁴
So, The total energy as a function of = 7.5 x 10⁻⁴
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To solve this problem we will apply the concept of rotational kinetic energy. Once this energy is found we will proceed to find the time from the definition of the power, which indicates the change of energy over time. Let's start with the kinetic energy of the rotating flywheel is
Here
I = moment of inertia
Angular velocity
Here we have that,
Replacing the value of the moment of inertia for this object we have,
The expression for average power is
Therefore the correct answer is 620s.