Answer:
See image attached.
Explanation:
This device features priority encoding of the inputs
to ensure that only the highest order data line is en-
coded. Nine input lines are encoded to a four line
BCD output. The implied decimal zero condition re-
quires no input condition as zero is encoded when
all nine datalinesare athigh logic level. Alldata input
and outputs are active at the low logic level. All in-
puts are equipped with protection circuits against
static discharge and transient excess voltage.
Answer:
Prevent electrical shock
Grounding is a non current carrying conductor mainly used to guard against hazards due to leakage in electric circuits
Explanation:
The grounding refers to the connection of an electrical equipment exposed metallic parts to the ground to serve as a source of current flow in the event of an insulation failure will cause the fuses to trip thereby isolating or removing electric power from the device
Grounding also prevents the accumulation of static electricity which can be a source of fire in inflammable areas.
Answer:
W=-109.12 kJ/kg
Q=-76.34 kJ/kg
Explanation:
The needed work W we will calculate by using the work equation for polytropic process and the heat transfer Q we will calculate by using the energy balance equation.
Before the calculations we first need to determine the final temperature T2. We will do that by using the given initial temperature T1 = 10°C, the given initial p_1 = 120 kPa and final p_2 = 800 kPa pressure and the polytropic index n = 1.2. Before the calculation we need to express the temperature in K units.
T1 = 10°C + 273 K = 283 K
T2 = ((p_2/p_1)^(n-1)/n)* T1
T2 = 388 K
Now we can use the heat capacity C_v, = 0.3122 kJ /kg K and the temperatures T1 and T2 to determine the change in internal energy ΔU.
ΔU = C_v*(T2-T1)
ΔU = 32.78 kJ/kg
to determine the work we will also need the initial v1 and final v2 specific volume. The initial specific volume v1 we can determine from the ideal gas equation. For the calculation we will need the initial pressure p_1, temperature T1 and the specific gas constant R = 0.2081 kJ /kg K.
v1=R*T1/p_1
v1=0.4908 m^3/kg
For the final specific volume we need to replace the initial temperature and pressure with the final.
v2=R*T2/p_2
v2=0.1009 m^3/kg
The work W is then:
W=p_2*v2-p_1*v1/n-1
W=-109.12 kJ/kg
The heat transfer Q we can calculate form the energy balance equation. For the calculation we will need the calculated work W and the change in internal energy ΔU.
Q=W+ΔU
Q=-76.34 kJ/kg
Answer:
Because if you think you're safe, you're more likely to take less caution when in an environment where PPE is necessary. By using faulty PPE, you are putting yourself and others more at risk.