Explanation:
most big airports. my father has the same degree and works for southwest airlines
Answer:
1. Slope = 53.3 x 10⁻⁶
2. Deflection = -0.00016m
Explanation:
given:
let L = 4 m (span of cantilever beam)
let w = 300 N/m (distributed load)
let EI =60 MNm² (flexural stiffness)
dy w * L³ 300 x 4³
1. slope = ------- = --------- = ------------------- = 53.3 x 10⁻⁶
dx 6EI 6 x 60x10⁶
wL⁴ 300 x 4⁴
2. Deflection = y = - ----------- = - ------------------ = -0.00016m
8EI 8 x 60x10⁶
therefore the deflection is 0.16mm downwards.
Answer:
H(s) = 20 / [ 1 + s / 10^5 ]^2
Explanation:
Given data:
cutoff frequency = 100 kHz
stopband attenuation rate = 40 dB/decade
nominal passband gain = 20 dB
new nominal passband gain at cutoff = 14 dB
<u>Represent the transfer function H(s)</u>
The attenuation rate show that there are two(2) poles
H(s) = k / [ 1 + s/Wc ]^2 ----- ( 1 )
where : Wc = 100 kHz = 10^5 Hz , K = 20 log k = 20 dB ∴ k = 20
Input values into equation 1
H(s) = 20 / [ 1 + s / 10^5 ]^2