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elena55 [62]
2 years ago
10

Two technicians are discussing torsion bars. Technician A says that many torsion bars are adjustable to allow for ride height ad

justment. Technician B says that torsion bars are usually marked left and right and should not be switched side to side. Which technician is correct
Engineering
1 answer:
sergij07 [2.7K]2 years ago
7 0

Answer: try asking googol or sirl

Explanation:

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Explain the differences between 1- Energy 2- Power 3- Work 4- Heat Your answer should explain the mathematica and physical meani
vazorg [7]

Answer:

Explanation:

Energy : Energy can be defined as both qualitative and quantitative property that can be given to an object in the form of work or heat.

For example - water stored in a tank at a height,h from the ground has a potential energy of U = ρgh.

Mathematically, Energy of water stored in a tank is

                      U = ρ.g.h

where, ρ is  water density

            g is acceleration due to gravity

            h is height of water tank from ground

Power : Power is defined as rate at which work can be done.

For example - When a force F is applied to an object to move it through a distance d in time t seconds is an example of power delivered.

Mathematically, Power = Work done / Time

                         P = \frac{F\times  d}{t}

                                P = \frac{W}{t}

Work : When a force act on a body and the body moves, work is said to be done.

For example - Gas confined in a cylinder by a piston. The gas expands when it is heated, doing work on the piston.

Mathematically, Work,W = F X d

where, F is force

            d is distance

Heat : Heat is a form of energy which is produced as a result of motion of atoms and particles.

For example - while increasing the temperature of water, heat is added to the water by means of gas burner or any other form.

Mathematically we can calculate heat release or heat absorb by

    q = m.C.ΔT

where q is heat

           m is mass

           C is specific heat capacity

           ΔT is change in temperature

4 0
3 years ago
A very large plate is placed equidistant between two vertical walls. The 10-mm spacing between the plate and each wall is filled
Vikentia [17]

Answer:

Force per unit plate area is 0.1344 N/m^{2}

Solution:

As per the question:

The spacing between each wall and the plate, d = 10 mm = 0.01 m

Absolute viscosity of the liquid, \mu =1.92\times 10^{- 3} Pa-s

Speed, v = 35 mm/s = 0.035 m/s

Now,

Suppose the drag force that exist between each wall and plate is F and F' respectively:

Net Drag Force = F' + F''

F = \tau A

where

\tau = shear stress

A = Cross - sectional Area

Therefore,

Net Drag Force, F = (\tau ' +\tau '')A

\frac{F}{A} = \tau ' +\tau ''

Also

F = \frac{\mu v}{d}

where

\mu = dynamic coefficient of viscosity

Pressure, P = \frac{F}{A}

Therefore,

\frac{F}{A} = \frac{\mu v}{d} + \frac{\mu v}{d} = 2\frac{\mu v}{d}

\frac{F}{A} = 2\frac{1.92\times 10^{- 3}\times 0.035}{0.010} = 0.01344 N/m^{2}

8 0
3 years ago
What is a magnitute?
ValentinkaMS [17]

Answer:

Magnitude is a specific type of norm. Magnitude is what is known as the Euclidean norm. There are other norms, such as the Leibniz and the Chebychev norm.

Explanation:

5 0
3 years ago
Read 2 more answers
A large spherical tank contains gas at a pressure of 400 psi. The tank is constructed of high-strength steel having a yield stre
jok3333 [9.3K]

Answer:

t=2.025 inches

Explanation:

Given that

P = 400 Psi

Yield stress ,σ = 80 ksi

Diameter ,d= 45 ft

We know that

1 ft = 12 inches

d= 540 inches

Factor of safety ,K= 3

The required thickness given as

\dfrac {Pd}{4t}=\dfrac{\sigma}{K}

t=thickness

\dfrac {PdK}{4\sigma}=t

\dfrac {400\times 540\times 3}{4\times 80\times 1000}=t

t=2.025 inches

Therefore thickness will be 2.025 inches.

5 0
3 years ago
Indicate on a tensile curve such quantities as yield stress, Young's modulus, UTS, toughness, point of necking, point of fractur
Illusion [34]

Explanation:

Step1

In the stress-strain curve of any material, the yield stress is the maximum stress at which material starts yielding.

Step2

Young’s modulus is the constant of proportionality of stress and strain according to hooks law. It is the slope of the slope of the stress-strain curve of the any material under proportional limit.

Step3

Ultimate tensile stress is the maximum stress that induced in the material under application of load.

Step4

Toughness is the strain energy per unit volume up to the fracture point of the stress-strain diagram of any material. This is the area under the curve of stress-strain.

Step5

Point of necking is the point where any material starts necking under application of load in necking region of the stress-strain curve.

Step6

Fracture point is the last point of the stress-strain curve where component fractures under application of load.

All the parameters are shown in below stress-strain curve:

8 0
3 years ago
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