Answer:
at R/
Explanation:
The free-fall acceleration at the surface of Earth is given by
where
G is the gravitational constant
M is the Earth's mass
R is the Earth's radius
The formula can be rewritten as
(1)
We want to shrink the Earth at a radius R' such that the acceleration of gravity becomes 3 times the present value, so
g' = 3g
Keeping the mass constant, M, and substituting into the equation, we have
Answer:
For an object to be an equilibrium it must be experiencing no acceleration.
Explanation:
Hope it helps.
Answer:
19.9 N/m
Explanation:
From the question,
Applying Hook's law
F = Ke.................. Equation 1
Where F = Force on the spring, k = spring constant, e = extension
But the force on the spring is the weight of the mass
Therefore,
mg = ke.................. Equation 2
Where m = mass. g = acceleration due to gravity
make e the subject of the equation
e = mg/e................ Equation 3
Given: m = 455 g = 0.455 kg, e = 22.4 cm = 0.224 m,
Constant: g = 9.8 m/s²
Substitute these values into equation 3
e = (0.455×9.8)/0.224
e = 19.9 N/m
Answer and Explanation:
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Ranboo oobnar have a good day
