Answer:
Explanation:
Efficiency of a Carnot engine = 1 – (T2/T1)
;
where T1 = source temperature and T2 = sink temperature
T2 = 10⁰C = 273+10 = 283K
The initial efficiency = 40%
So 0.4 = 1 - (283/Initial T1)
Initial T1 = 283/(1-0.4) = 471.67 K
To raise efficiency to 65%
0.65 = 1 - (283/Increased T1)
Increased T1 = 283/(1-0.65) = 808.57 K
The source temperature must be increased by 808.57 - 471.67 = 336.9 K or 336.9°C.
Answer:
Work done is zero
Explanation:
given data
Angle of kite with horizontal = 30 degree
tension in the string = 4.5 N
WE KNOW THAT
Work = force * distance
horizontal force = 
DISTANCE = 0 as boy stands still. therefore
work done = 3.89 *0 = 0
Answer:
see from this analysis, the apparent weight of the body is lower due to the push created by the air brujuleas
Explanation:
We will propose this exercise using Archimedes' principle, which establishes that the thrust on a body is equal to the volume of the desalted liquid.
B = ρ g V
The weight of a submerged body is the net force between the weight and the thrust
F_net = W - B
we can write the weight as a function of the density
ρ_body = m / V
m = ρ_body V
W = mg
W = ρ _body g V
we substitute
F_net= ( ρ_body - ρ _fluid) g V
In general this force is directed downwards, we can call this value the apparent weight of the body. This is the weight of the submerged body.
W_aparente = ( ρ_body - ρ _fluid) g V
If some air bubbles formed in this body, the net force of these bubbles is
F_net ’= #_bubbles ( ρ_fluido - ρ_air) g V’
this force is directed upwards
whereby the measured force is
F = W_aparente - F_air
As we can see from this analysis, the apparent weight of the body is lower due to the push created by the air brujuleas
Ummm because it need space to move around and function
The slope of the distance/time graph is the speed of the moving object.
So the graph for a fast moving object will have a greater slope than the
graph for a slower moving object has.
